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Chemistry - Atomic Structure (Protons, Neutrons, Electrons, Valency, Isotopes)

Grade 8ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

An atom is the smallest unit of matter, consisting of a central nucleus and surrounding shells.

Protons (p+p^+) are positively charged particles located in the nucleus with a mass of 1 amu1 \text{ amu}.

Neutrons (n0n^0) are neutral particles found in the nucleus with a mass of approximately 1 amu1 \text{ amu}.

Electrons (ee^-) are negatively charged particles that revolve around the nucleus in fixed orbits. Their mass is negligible (1/1837 amu\approx 1/1837 \text{ amu}).

Atomic Number (ZZ) is defined as the number of protons in the nucleus of an atom. In a neutral atom, Z=number of protons=number of electronsZ = \text{number of protons} = \text{number of electrons}.

Mass Number (AA) is the sum of the number of protons and neutrons in the nucleus: A=p+nA = p + n.

Electronic Configuration describes the distribution of electrons in different shells (K,L,M,N...K, L, M, N...). The maximum number of electrons in a shell is governed by the 2n22n^2 rule.

Valency is the combining capacity of an atom. It is determined by the number of electrons in the outermost shell (valence electrons).

Isotopes are atoms of the same element that have the same Atomic Number (ZZ) but different Mass Numbers (AA). They have the same chemical properties but different physical properties.

📐Formulae

Z=pZ = p

A=p+nA = p + n

n=AZn = A - Z

Maximum electrons in nth shell=2n2\text{Maximum electrons in } n^{th} \text{ shell} = 2n^2

Valency (for metals)=Number of valence electrons\text{Valency (for metals)} = \text{Number of valence electrons}

Valency (for non-metals)=8Number of valence electrons\text{Valency (for non-metals)} = 8 - \text{Number of valence electrons}

💡Examples

Problem 1:

An element XX is represented as 1327X^{27}_{13}X. Calculate the number of protons, electrons, and neutrons present in it.

Solution:

p=13p = 13, e=13e = 13, n=14n = 14

Explanation:

From the notation ZAX^{A}_{Z}X, the Atomic Number Z=13Z = 13, so Protons (pp) = 1313. Since it is a neutral atom, Electrons (ee) = 1313. The Mass Number A=27A = 27. Number of Neutrons n=AZ=2713=14n = A - Z = 27 - 13 = 14.

Problem 2:

Determine the electronic configuration and valency of an atom with Atomic Number Z=16Z = 16.

Solution:

Configuration: 2,8,62, 8, 6; Valency: 22

Explanation:

With Z=16Z = 16, the electrons are distributed as: KK shell = 22, LL shell = 88, and MM shell = 66. Since there are 66 valence electrons, the atom needs 22 more to complete its octet. Therefore, Valency=86=2\text{Valency} = 8 - 6 = 2.

Problem 3:

Identify the isotopes of Hydrogen and write their notation.

Solution:

Protium (11H^1_1H), Deuterium (12H^2_1H), and Tritium (13H^3_1H)

Explanation:

All three have the same atomic number (Z=1Z=1) but different mass numbers (A=1,2,3A=1, 2, 3 respectively) due to differing numbers of neutrons (0,1,20, 1, 2).

Atomic Structure (Protons, Neutrons, Electrons, Valency, Isotopes) Revision - Class 8 Science ICSE