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Chemistry: Properties of Matter - The Periodic Table and Element Trends

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Periodic Table is arranged by increasing Atomic Number (ZZ), which represents the number of protons in the nucleus.

Groups (vertical columns) contain elements with the same number of valence electrons, resulting in similar chemical properties.

Periods (horizontal rows) indicate the number of occupied electron shells in an atom.

Metals are located on the left and center of the table; they typically lose electrons to form positive cations (Mn+M^{n+}).

Non-metals are located on the right side; they typically gain electrons to form negative anions (XnX^{n-}).

Atomic Radius: Generally increases down a group (more shells) and decreases across a period from left to right (greater nuclear charge pulling electrons closer).

Group 1 (Alkali Metals): Reactivity increases down the group because the valence electron is further from the nucleus (Li<Na<K<RbLi < Na < K < Rb).

Group 17 (Halogens): Reactivity decreases down the group as it becomes harder to attract an incoming electron (F>Cl>Br>IF > Cl > Br > I).

Group 18 (Noble Gases): Possess a full valence shell (e.g., 22 or 88 electrons), making them chemically inert/unreactive.

📐Formulae

A=Z+NA = Z + N

Net Charge=p+e\text{Net Charge} = p^+ - e^-

Max Electrons per Shell=2n2\text{Max Electrons per Shell} = 2n^2

Number of Neutrons(N)=Mass Number(A)Atomic Number(Z)\text{Number of Neutrons} (N) = \text{Mass Number} (A) - \text{Atomic Number} (Z)

💡Examples

Problem 1:

An isotope of Phosphorus has an atomic number Z=15Z = 15 and a mass number A=31A = 31. Calculate the number of neutrons (NN) and provide the electronic configuration for a neutral Phosphorus atom.

Solution:

N=16N = 16; Electronic Configuration: 2,8,52, 8, 5.

Explanation:

The number of neutrons is found using N=AZ=3115=16N = A - Z = 31 - 15 = 16. For a neutral atom, electrons equal protons (1515). Following the 2,8,82, 8, 8 rule, the first shell holds 22, the second holds 88, and the remaining 55 go into the third shell.

Problem 2:

Magnesium (MgMg) is in Group 2. Predict the charge of a Magnesium ion and write its chemical symbol with the charge.

Solution:

Mg2+Mg^{2+}

Explanation:

Elements in Group 2 have 22 valence electrons. To achieve a stable full outer shell, Magnesium loses these 22 electrons. Since it loses two negative charges, the resulting ion has a charge of +2+2.

Problem 3:

Compare the atomic radius of Sodium (NaNa, Z=11Z=11) and Chlorine (ClCl, Z=17Z=17), both in Period 3.

Solution:

The atomic radius of NaNa is larger than the atomic radius of ClCl.

Explanation:

Both elements have electrons in three shells. However, Chlorine has more protons (1717) than Sodium (1111). This higher nuclear charge exerts a stronger pull on the electrons, drawing them closer to the nucleus and making the atom smaller.

The Periodic Table and Element Trends - Revision Notes & Key Formulas | IB Grade 8 Science