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Chemistry: Properties of Matter - Chemical vs. Physical Changes

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Matter is defined as anything that has mass (mm) and occupies volume (VV). Its properties are categorized into physical and chemical characteristics.

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Physical Properties can be observed or measured without changing the identity of the substance. Examples include density (ρ=mV\rho = \frac{m}{V}), boiling point, and solubility.

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Physical Changes involve a change in the state or appearance of matter but not its chemical composition. These are often reversible, such as the phase transition of water: H2O(s)⇌H2O(l)H_2O(s) \rightleftharpoons H_2O(l).

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Chemical Properties describe the ability of a substance to undergo a specific chemical change. Examples include flammability and reactivity with acids.

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Chemical Changes result in the formation of one or more new substances with different properties. This involves the breaking and forming of chemical bonds, such as the combustion of methane: CH4+2O2→CO2+2H2OCH_4 + 2O_2 \rightarrow CO_2 + 2H_2O.

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Evidence of a chemical change includes: color change, evolution of a gas (bubbles), formation of a precipitate (solid from two liquids), and temperature change (ΔT\Delta T).

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The Law of Conservation of Mass states that in a closed system, mass is neither created nor destroyed. Therefore, Massreactants=MassproductsMass_{reactants} = Mass_{products}.

📐Formulae

ρ=mV\rho = \frac{m}{V}

∑mreactants=∑mproducts\sum m_{reactants} = \sum m_{products}

ΔQ=mcΔT\Delta Q = m c \Delta T

2H2(g)+O2(g)→2H2O(l)2H_2(g) + O_2(g) \rightarrow 2H_2O(l)

💡Examples

Problem 1:

During an experiment, 10.0 g10.0\,g of Magnesium (MgMg) is burned in oxygen to produce 16.6 g16.6\,g of Magnesium Oxide (MgOMgO). Calculate the mass of Oxygen (O2O_2) consumed in the reaction.

Solution:

6.6 g6.6\,g

Explanation:

According to the Law of Conservation of Mass, the mass of reactants must equal the mass of products. Let xx be the mass of O2O_2. Thus, 10.0 g (Mg)+x (O2)=16.6 g (MgO)10.0\,g\,(Mg) + x\,(O_2) = 16.6\,g\,(MgO). Solving for xx: x=16.6 g−10.0 g=6.6 gx = 16.6\,g - 10.0\,g = 6.6\,g.

Problem 2:

Identify the type of change occurring when an iron nail (FeFe) develops a layer of rust (Fe2O3⋅nH2OFe_2O_3 \cdot nH_2O) after being left in a damp environment.

Solution:

Chemical Change

Explanation:

The iron atoms react with oxygen and water in the environment to form a new substance, hydrated iron(III) oxide. Since a new chemical substance is formed with different properties than the original iron, it is a chemical change.

Problem 3:

Is the dissolving of sugar (C12H22O11C_{12}H_{22}O_{11}) in water (H2OH_2O) a physical or chemical change?

Solution:

Physical Change

Explanation:

Dissolving is a physical change because the chemical identity of the sugar molecules remains unchanged. The sugar can be recovered by evaporating the water (H2OH_2O), showing that the process is reversible without a chemical reaction.