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Chemistry: Properties of Matter - Chemical vs. Physical Changes

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Matter is defined as anything that has mass (mm) and occupies volume (VV). Its properties are categorized into physical and chemical characteristics.

Physical Properties can be observed or measured without changing the identity of the substance. Examples include density (ρ=mV\rho = \frac{m}{V}), boiling point, and solubility.

Physical Changes involve a change in the state or appearance of matter but not its chemical composition. These are often reversible, such as the phase transition of water: H2O(s)H2O(l)H_2O(s) \rightleftharpoons H_2O(l).

Chemical Properties describe the ability of a substance to undergo a specific chemical change. Examples include flammability and reactivity with acids.

Chemical Changes result in the formation of one or more new substances with different properties. This involves the breaking and forming of chemical bonds, such as the combustion of methane: CH4+2O2CO2+2H2OCH_4 + 2O_2 \rightarrow CO_2 + 2H_2O.

Evidence of a chemical change includes: color change, evolution of a gas (bubbles), formation of a precipitate (solid from two liquids), and temperature change (ΔT\Delta T).

The Law of Conservation of Mass states that in a closed system, mass is neither created nor destroyed. Therefore, Massreactants=MassproductsMass_{reactants} = Mass_{products}.

📐Formulae

ρ=mV\rho = \frac{m}{V}

mreactants=mproducts\sum m_{reactants} = \sum m_{products}

ΔQ=mcΔT\Delta Q = m c \Delta T

2H2(g)+O2(g)2H2O(l)2H_2(g) + O_2(g) \rightarrow 2H_2O(l)

💡Examples

Problem 1:

During an experiment, 10.0g10.0\,g of Magnesium (MgMg) is burned in oxygen to produce 16.6g16.6\,g of Magnesium Oxide (MgOMgO). Calculate the mass of Oxygen (O2O_2) consumed in the reaction.

Solution:

6.6g6.6\,g

Explanation:

According to the Law of Conservation of Mass, the mass of reactants must equal the mass of products. Let xx be the mass of O2O_2. Thus, 10.0g(Mg)+x(O2)=16.6g(MgO)10.0\,g\,(Mg) + x\,(O_2) = 16.6\,g\,(MgO). Solving for xx: x=16.6g10.0g=6.6gx = 16.6\,g - 10.0\,g = 6.6\,g.

Problem 2:

Identify the type of change occurring when an iron nail (FeFe) develops a layer of rust (Fe2O3nH2OFe_2O_3 \cdot nH_2O) after being left in a damp environment.

Solution:

Chemical Change

Explanation:

The iron atoms react with oxygen and water in the environment to form a new substance, hydrated iron(III) oxide. Since a new chemical substance is formed with different properties than the original iron, it is a chemical change.

Problem 3:

Is the dissolving of sugar (C12H22O11C_{12}H_{22}O_{11}) in water (H2OH_2O) a physical or chemical change?

Solution:

Physical Change

Explanation:

Dissolving is a physical change because the chemical identity of the sugar molecules remains unchanged. The sugar can be recovered by evaporating the water (H2OH_2O), showing that the process is reversible without a chemical reaction.

Chemical vs. Physical Changes - Revision Notes & Key Formulas | IB Grade 8 Science