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Chemistry: Properties of Matter - Chemical Bonding and Naming Compounds

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Valence Electrons: These are the electrons in the outermost shell of an atom. They determine how an atom bonds. For example, Carbon has 44 valence electrons.

The Octet Rule: Atoms tend to gain, lose, or share electrons to achieve a stable electron configuration with 88 valence electrons, similar to noble gases.

Ionic Bonding: Formed through the transfer of electrons from a metal to a non-metal. This results in the formation of a cation (++) and an anion (-), held together by electrostatic forces, such as in NaClNaCl.

Covalent Bonding: Formed when two non-metals share pairs of electrons to achieve stability. A single bond involves one pair (22 electrons), like in H2H_2.

Naming Ionic Compounds: The metal (cation) is named first, followed by the non-metal (anion) with the suffix '-ide'. For transition metals, the charge is indicated with Roman numerals, e.g., FeCl3FeCl_3 is Iron(III) chloride.

Polyatomic Ions: Groups of atoms that act as a single charged unit, such as Sulfate (SO42SO_4^{2-}) or Nitrate (NO3NO_3^{-}).

Naming Covalent Compounds: Prefixes (mono-, di-, tri-, tetra-, etc.) are used to indicate the number of atoms of each element. For example, CO2CO_2 is Carbon dioxide and N2O4N_2O_4 is Dinitrogen tetroxide.

📐Formulae

Total Charge of Ionic Compound=0\text{Total Charge of Ionic Compound} = 0

Number of atoms×Oxidation State=Net Charge\text{Number of atoms} \times \text{Oxidation State} = \text{Net Charge}

Al3++O2Al2O3Al^{3+} + O^{2-} \rightarrow Al_2O_3

CnH2n+2 (General formula for Alkanes)C_n H_{2n+2} \text{ (General formula for Alkanes)}

💡Examples

Problem 1:

Write the chemical formula for the ionic compound formed between Magnesium (MgMg) and Nitrogen (NN).

Solution:

Mg3N2Mg_3N_2

Explanation:

Magnesium is in Group 2 and forms a Mg2+Mg^{2+} ion. Nitrogen is in Group 15 and forms a N3N^{3-} ion. To balance the charges to zero: 3(2+)+2(3)=66=03(2+) + 2(3-) = 6 - 6 = 0. Therefore, the formula is Mg3N2Mg_3N_2.

Problem 2:

Name the covalent compound with the formula P2O5P_2O_5.

Solution:

Diphosphorus pentoxide

Explanation:

Using covalent naming prefixes: 'di-' for 22 Phosphorus atoms and 'penta-' (shortened to pent- before oxide) for 55 Oxygen atoms.

Problem 3:

Identify the type of bond in HClHCl and CaOCaO.

Solution:

HClHCl is Covalent; CaOCaO is Ionic.

Explanation:

HClHCl consists of two non-metals sharing electrons, forming a polar covalent bond. CaOCaO consists of a metal (CaCa) and a non-metal (OO), involving the transfer of electrons from CaCa to OO.

Chemical Bonding and Naming Compounds - Revision Notes & Key Formulas | IB Grade 8 Science