krit.club logo

Chemistry: Properties of Matter - Atomic Structure (Protons, Neutrons, Electrons)

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

The atom is the basic building block of matter, consisting of a central nucleus and surrounding electron shells.

•

The nucleus contains protons (p+p^+) which have a positive charge of +1+1 and a relative mass of 11, and neutrons (n0n^0) which have a neutral charge and a relative mass of 11.

•

Electrons (e−e^-) orbit the nucleus in specific energy levels or shells; they have a negative charge of −1-1 and a negligible mass (approximately 11840\frac{1}{1840} of a proton).

•

The Atomic Number (ZZ) is the number of protons in the nucleus and defines the identity of the element.

•

The Mass Number (AA) is the total number of protons and neutrons in the nucleus.

•

In a neutral atom, the number of protons is equal to the number of electrons, resulting in a net charge of 00.

•

Isotopes are atoms of the same element that have the same number of protons but a different number of neutrons, resulting in different mass numbers (e.g., 612C^{12}_{6}C and 614C^{14}_{6}C).

•

Standard nuclide notation is written as ZAX^{A}_{Z}X, where XX is the chemical symbol, AA is the mass number, and ZZ is the atomic number.

📐Formulae

A=Z+NA = Z + N

N=A−ZN = A - Z

Net Charge=number of protons−number of electrons\text{Net Charge} = \text{number of protons} - \text{number of electrons}

Mass of Atom≈Mass of Protons+Mass of Neutrons\text{Mass of Atom} \approx \text{Mass of Protons} + \text{Mass of Neutrons}

💡Examples

Problem 1:

An atom of Sodium is represented as 1123Na^{23}_{11}Na. Determine the number of protons, neutrons, and electrons in a neutral atom.

Solution:

Protons = 1111, Electrons = 1111, Neutrons = 1212.

Explanation:

The atomic number Z=11Z = 11 indicates there are 1111 protons. In a neutral atom, protons equal electrons (1111). The number of neutrons NN is calculated using A−ZA - Z, which is 23−11=1223 - 11 = 12.

Problem 2:

An ion of Magnesium (Mg2+Mg^{2+}) has an atomic number of 1212 and a mass number of 2424. Calculate the number of subatomic particles.

Solution:

Protons = 1212, Neutrons = 1212, Electrons = 1010.

Explanation:

Protons are determined by the atomic number (1212). Neutrons are A−Z=24−12=12A - Z = 24 - 12 = 12. Since the ion has a charge of +2+2, it has lost 22 electrons: 12−2=1012 - 2 = 10 electrons.

Problem 3:

Identify the element and its mass number if it has 1717 protons and 1818 neutrons.

Solution:

Element: Chlorine (ClCl), Mass Number (AA) = 3535.

Explanation:

The atomic number Z=17Z = 17 corresponds to Chlorine on the Periodic Table. The mass number is the sum of protons and neutrons: 17+18=3517 + 18 = 35.