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Sound - Production and Propagation of Sound

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Sound is a form of energy produced by vibrating objects. Vibration is the rapid to-and-forth motion of an object about its mean position.

In humans, sound is produced by the larynx (voice box). Two vocal cords are stretched across the larynx such that they leave a narrow slit for the passage of air; air expelled by the lungs makes the cords vibrate.

Sound requires a medium (solid, liquid, or gas) to propagate. It cannot travel through a vacuum because there are no molecules to compress and rarefy.

The speed of sound depends on the nature of the medium. Generally, Vsolid>Vliquid>VgasV_{solid} > V_{liquid} > V_{gas}.

Amplitude (AA) is the maximum displacement of a vibrating object from its central position. It determines the loudness of the sound. LoudnessAmplitude2\text{Loudness} \propto \text{Amplitude}^2.

Frequency (ff) is the number of oscillations per second, measured in Hertz (HzHz). It determines the pitch or shrillness of the sound.

The time taken for one complete oscillation is called the Time Period (TT). The relationship is T=1fT = \frac{1}{f}.

The audible range of frequencies for the human ear is roughly between 20 Hz20\text{ Hz} and 20,000 Hz20,000\text{ Hz}.

Unpleasant sounds are termed as noise, while pleasing sounds are called music. Excessive or unwanted sound in the environment is called noise pollution.

📐Formulae

f=Number of OscillationsTime in secondsf = \frac{\text{Number of Oscillations}}{\text{Time in seconds}}

T=1fT = \frac{1}{f}

Loudness(Amplitude)2\text{Loudness} \propto (\text{Amplitude})^2

Speed(v)=DistanceTime\text{Speed} (v) = \frac{\text{Distance}}{\text{Time}}

💡Examples

Problem 1:

A simple pendulum makes 2020 oscillations in 4040 seconds. What is its frequency and time period?

Solution:

Frequency f=2040=0.5 Hzf = \frac{20}{40} = 0.5\text{ Hz}. Time Period T=10.5=2 sT = \frac{1}{0.5} = 2\text{ s}.

Explanation:

Frequency is calculated as the number of oscillations per unit time. The time period is the reciprocal of the frequency.

Problem 2:

If the amplitude of a vibrating body is doubled, by how much does the loudness increase?

Solution:

The loudness will increase by 44 times (222^2).

Explanation:

Since LoudnessAmplitude2\text{Loudness} \propto \text{Amplitude}^2, if the amplitude becomes 2A2A, the new loudness is proportional to (2A)2=4A2(2A)^2 = 4A^2.

Problem 3:

A lightning strike is seen, and the thunder is heard 33 seconds later. If the speed of sound is 340 m/s340\text{ m/s}, calculate the distance of the lightning strike.

Solution:

Distance =Speed×Time=340 m/s×3 s=1020 m= \text{Speed} \times \text{Time} = 340\text{ m/s} \times 3\text{ s} = 1020\text{ m}.

Explanation:

Light travels much faster than sound, so we see lightning almost instantly. The distance can be found using the speed of sound and the time delay of the thunder.

Production and Propagation of Sound - Revision Notes & Key Formulas | CBSE Class 8 Science