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Sound - Production and Propagation of Sound

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Sound is a form of energy produced by vibrating objects. Vibration is the rapid to-and-forth motion of an object about its mean position.

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In humans, sound is produced by the larynx (voice box). Two vocal cords are stretched across the larynx such that they leave a narrow slit for the passage of air; air expelled by the lungs makes the cords vibrate.

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Sound requires a medium (solid, liquid, or gas) to propagate. It cannot travel through a vacuum because there are no molecules to compress and rarefy.

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The speed of sound depends on the nature of the medium. Generally, Vsolid>Vliquid>VgasV_{solid} > V_{liquid} > V_{gas}.

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Amplitude (AA) is the maximum displacement of a vibrating object from its central position. It determines the loudness of the sound. Loudness∝Amplitude2\text{Loudness} \propto \text{Amplitude}^2.

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Frequency (ff) is the number of oscillations per second, measured in Hertz (HzHz). It determines the pitch or shrillness of the sound.

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The time taken for one complete oscillation is called the Time Period (TT). The relationship is T=1fT = \frac{1}{f}.

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The audible range of frequencies for the human ear is roughly between 20 Hz20\text{ Hz} and 20,000 Hz20,000\text{ Hz}.

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Unpleasant sounds are termed as noise, while pleasing sounds are called music. Excessive or unwanted sound in the environment is called noise pollution.

📐Formulae

f=Number of OscillationsTime in secondsf = \frac{\text{Number of Oscillations}}{\text{Time in seconds}}

T=1fT = \frac{1}{f}

Loudness∝(Amplitude)2\text{Loudness} \propto (\text{Amplitude})^2

Speed(v)=DistanceTime\text{Speed} (v) = \frac{\text{Distance}}{\text{Time}}

💡Examples

Problem 1:

A simple pendulum makes 2020 oscillations in 4040 seconds. What is its frequency and time period?

Solution:

Frequency f=2040=0.5 Hzf = \frac{20}{40} = 0.5\text{ Hz}. Time Period T=10.5=2 sT = \frac{1}{0.5} = 2\text{ s}.

Explanation:

Frequency is calculated as the number of oscillations per unit time. The time period is the reciprocal of the frequency.

Problem 2:

If the amplitude of a vibrating body is doubled, by how much does the loudness increase?

Solution:

The loudness will increase by 44 times (222^2).

Explanation:

Since Loudness∝Amplitude2\text{Loudness} \propto \text{Amplitude}^2, if the amplitude becomes 2A2A, the new loudness is proportional to (2A)2=4A2(2A)^2 = 4A^2.

Problem 3:

A lightning strike is seen, and the thunder is heard 33 seconds later. If the speed of sound is 340 m/s340\text{ m/s}, calculate the distance of the lightning strike.

Solution:

Distance =Speed×Time=340 m/s×3 s=1020 m= \text{Speed} \times \text{Time} = 340\text{ m/s} \times 3\text{ s} = 1020\text{ m}.

Explanation:

Light travels much faster than sound, so we see lightning almost instantly. The distance can be found using the speed of sound and the time delay of the thunder.