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Particulate Nature of Matter - Melting point and Change of State

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Matter is composed of tiny particles that are in constant motion. In a solid, these particles are held together by strong inter-particle forces of attraction.

The melting point is the temperature at which a solid starts changing into a liquid at atmospheric pressure. At this point, the kinetic energy of particles is sufficient to overcome the forces of attraction. For ice, this is 0C0^\circ \text{C} or 273.15 K273.15 \text{ K}.

During the change of state from solid to liquid, the temperature remains constant until the entire substance has melted. The heat energy supplied is used to change the state by breaking the bonds between particles, rather than increasing the temperature.

Latent Heat of Fusion is the amount of heat energy required to change 1 kg1 \text{ kg} of a solid into a liquid at its melting point at atmospheric pressure. It is called 'latent' or hidden because it does not show a rise in temperature on the thermometer.

Particles in water at 0C0^\circ \text{C} (273 K273 \text{ K}) have more energy than particles in ice at the same temperature because the water particles have absorbed the Latent Heat of Fusion.

📐Formulae

T(K)=T(C)+273.15T(\text{K}) = T(^\circ \text{C}) + 273.15

Q=mLfQ = m \cdot L_f

💡Examples

Problem 1:

Convert a temperature of 373 K373 \text{ K} to the Celsius scale.

Solution:

T(C)=373273.15=99.85CT(^\circ \text{C}) = 373 - 273.15 = 99.85^\circ \text{C}

Explanation:

To convert from Kelvin to Celsius, we subtract 273.15273.15 (or simply 273273 for Grade 8 level calculations) from the Kelvin temperature value.

Problem 2:

Why is the temperature of melting ice constant at 0C0^\circ \text{C} even though we continue to heat it?

Solution:

The heat is absorbed as Latent Heat of Fusion.

Explanation:

When ice reaches 0C0^\circ \text{C}, the heat energy being supplied is used to overcome the intermolecular forces of attraction between the H2OH_2O molecules to convert them from a solid lattice to a liquid state. Since this energy is consumed in the change of state, the kinetic energy of the particles does not increase, and thus the temperature remains constant.

Problem 3:

Calculate the temperature in Kelvin for the boiling point of water, which is 100C100^\circ \text{C}.

Solution:

T(K)=100+273=373 KT(\text{K}) = 100 + 273 = 373 \text{ K}

Explanation:

Using the formula T(K)=T(C)+273T(\text{K}) = T(^\circ \text{C}) + 273, we add 273273 to the Celsius value of the boiling point.

Melting point and Change of State - Revision Notes & Key Formulas | CBSE Class 8 Science