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Electricity: Magnetic and Heating Effects - Electric Fuse and Safety Devices

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Heating Effect of Electric Current: When an electric current flows through a wire, the wire gets hot. This is known as the heating effect of current, governed by Joule's Law of Heating where heat HH is produced.

Electric Fuse: A safety device used in electrical circuits. It contains a wire made of a special alloy (like tin and lead) that has a low melting point. If the current II exceeds a safe limit, the wire melts and breaks the circuit.

Causes of Excessive Current: Two main reasons for high current are 'Short Circuit' (when live and neutral wires touch directly) and 'Overloading' (connecting too many appliances to a single socket).

MCB (Miniature Circuit Breaker): These are switches that automatically turn off when current in a circuit exceeds the safe limit. They are preferred over fuses because they can be reset manually without needing replacement.

Magnetic Effect of Electric Current: Discovered by Hans Christian Oersted, this principle states that a current-carrying conductor produces a magnetic field around it.

Electromagnet: A coil of insulated wire wound around a soft iron core. It acts as a magnet only as long as the electric current flows through it. Its strength depends on the current II and the number of turns nn in the coil.

Electric Bell: A device that works on the principle of the magnetic effect of current. It uses an electromagnet to pull an iron strip (armature) to strike a gong.

📐Formulae

H=I2RtH = I^2 R t

P=VimesIP = V imes I

I=PVI = \frac{P}{V}

💡Examples

Problem 1:

An electric heater is rated at 2000 W2000\text{ W} and is connected to a 220 V220\text{ V} supply. What should be the minimum rating of the fuse used for this heater?

Solution:

Current I=PV=2000 W220 V9.09 AI = \frac{P}{V} = \frac{2000\text{ W}}{220\text{ V}} \approx 9.09\text{ A}.

Explanation:

Since the heater draws approximately 9.09 A9.09\text{ A}, a fuse with a rating slightly higher than this, such as a 10 A10\text{ A} fuse, should be used to ensure safety without frequent blowing.

Problem 2:

Explain why a copper wire cannot be used as a fuse wire.

Solution:

Copper has a very high melting point and low resistance.

Explanation:

A fuse wire must melt easily when current II is excessive. Because copper has a high melting point, it will not melt even if the current is dangerously high, failing to break the circuit and potentially causing a fire.

Problem 3:

How does the strength of an electromagnet change if the number of turns in the coil is doubled?

Solution:

The magnetic strength also doubles.

Explanation:

The magnetic field strength BB of an electromagnet is directly proportional to the number of turns nn in the coil. Mathematically, BnB \propto n.

Electric Fuse and Safety Devices - Revision Notes & Key Formulas | CBSE Class 8 Science