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Earth and Space - The Solar System and Planets

Grade 7IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Solar System consists of the Sun, eight planets, their moons, and smaller objects like asteroids and comets. The planets in order from the Sun are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

The four inner planets (Mercury,Venus,Earth,MarsMercury, Venus, Earth, Mars) are terrestrial planets, meaning they are rocky and relatively small.

The four outer planets (Jupiter,Saturn,Uranus,NeptuneJupiter, Saturn, Uranus, Neptune) are gas giants or ice giants, composed primarily of hydrogen (H2H_2), helium (HeHe), and ices like water (H2OH_2O) and methane (CH4CH_4).

Gravity is the force that keeps planets in orbit around the Sun. The gravitational pull depends on the mass (mm) of the objects and the distance (rr) between them.

Mass is the amount of matter in an object (measured in kgkg), while Weight is the force of gravity acting on that mass (measured in NN). The gravitational field strength (gg) on Earth is approximately 9.8 N/kg9.8 \text{ N/kg}, while on the Moon it is approximately 1.6 N/kg1.6 \text{ N/kg}.

Distances in the solar system are often measured in Astronomical Units (AUAU), where 1 AU1.5×108 km1 \text{ AU} \approx 1.5 \times 10^8 \text{ km}, representing the average distance from the Earth to the Sun.

📐Formulae

W=m×gW = m \times g

v=2πrTv = \frac{2\pi r}{T}

F=Gm1m2r2F = G \frac{m_1 m_2}{r^2}

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

💡Examples

Problem 1:

An astronaut has a mass of 70 kg70 \text{ kg}. Calculate their weight on Earth (g=9.8 N/kgg = 9.8 \text{ N/kg}) and on Mars (g=3.7 N/kgg = 3.7 \text{ N/kg}).

Solution:

Weight on Earth: W=70 kg×9.8 N/kg=686 NW = 70 \text{ kg} \times 9.8 \text{ N/kg} = 686 \text{ N}. Weight on Mars: W=70 kg×3.7 N/kg=259 NW = 70 \text{ kg} \times 3.7 \text{ N/kg} = 259 \text{ N}.

Explanation:

Weight is calculated by multiplying mass by the local gravitational field strength. Mass remains constant regardless of location.

Problem 2:

Light travels at a speed of approximately 3×105 km/s3 \times 10^5 \text{ km/s}. If the Sun is 1.5×108 km1.5 \times 10^8 \text{ km} away from Earth, how long does it take for sunlight to reach us in minutes?

Solution:

t=dv=1.5×108 km3×105 km/s=500 secondst = \frac{d}{v} = \frac{1.5 \times 10^8 \text{ km}}{3 \times 10^5 \text{ km/s}} = 500 \text{ seconds} In minutes: 500608.33 minutes\text{In minutes: } \frac{500}{60} \approx 8.33 \text{ minutes}

Explanation:

Using the speed, distance, time formula, we find the time in seconds and convert it to minutes by dividing by 6060.

The Solar System and Planets - Revision Notes & Key Formulas | IGCSE Grade 7 Science