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Earth and Space - The Earth, Moon, and Sun Cycles

Grade 7IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Earth rotates on its axis from West to East once every 2424 hours, which creates the cycle of day and night.

The Earth's axis is tilted at an angle of 23.523.5^\circ relative to its orbit around the Sun. This tilt is the primary cause of the seasons.

Earth orbits (revolves) around the Sun in an elliptical path, taking approximately 365.25365.25 days to complete one revolution.

The Moon orbits the Earth approximately every 27.327.3 days (sidereal month), but the cycle of Moon phases (synodic month) takes about 29.529.5 days due to the Earth's movement around the Sun.

Moon phases (New Moon, Waxing Crescent, First Quarter, Waxing Gibbous, Full Moon, Waning Gibbous, Last Quarter, Waning Crescent) are caused by the changing relative positions of the Earth, Moon, and Sun.

A Solar Eclipse occurs when the Moon passes directly between the Sun and Earth (SunMoonEarthSun \rightarrow Moon \rightarrow Earth), casting a shadow on Earth.

A Lunar Eclipse occurs when the Earth passes directly between the Sun and Moon (SunEarthMoonSun \rightarrow Earth \rightarrow Moon), casting the Earth's shadow on the Moon.

Tides are primarily caused by the gravitational pull of the Moon and, to a lesser extent, the Sun on Earth's oceans.

📐Formulae

1 Day=24 hours1 \text{ Day} = 24 \text{ hours}

1 Year365.25 days1 \text{ Year} \approx 365.25 \text{ days}

Orbital Speed(v)=2πrT\text{Orbital Speed} (v) = \frac{2\pi r}{T}

Tilt of Earth’s Axis=23.5\text{Tilt of Earth's Axis} = 23.5^\circ

💡Examples

Problem 1:

Explain why a 'Leap Year' occurs every four years in the Gregorian calendar.

Solution:

A leap year adds one extra day (366366 days total) to the calendar every four years.

Explanation:

Since the Earth takes approximately 365.25365.25 days to orbit the Sun, the 0.250.25 day is ignored for three years. In the fourth year, these fractions are summed: 0.25+0.25+0.25+0.25=1.00.25 + 0.25 + 0.25 + 0.25 = 1.0 day. This ensures the calendar remains synchronized with the Earth's astronomical seasons.

Problem 2:

During which season is the Northern Hemisphere tilted away from the Sun, and what is the effect on daylight hours?

Solution:

The Northern Hemisphere is tilted away from the Sun during the Winter Solstice (around December 21st).

Explanation:

When the Northern Hemisphere is tilted at 23.5-23.5^\circ relative to the Sun's direct rays, the Sun appears lower in the sky. This results in shorter daylight hours and less concentrated solar energy per unit area, leading to colder temperatures.

Problem 3:

Calculate the approximate orbital speed of the Earth if its average distance from the Sun (rr) is 1.5×108 km1.5 \times 10^8 \text{ km} and the period (TT) is 365365 days.

Solution:

v107,000 km/hv \approx 107,000 \text{ km/h}

Explanation:

Using the formula v=2πrTv = \frac{2\pi r}{T}, where r=150,000,000 kmr = 150,000,000 \text{ km} and T=365×24 hours=8760 hoursT = 365 \times 24 \text{ hours} = 8760 \text{ hours}. Substituting the values: v=2×3.14159×1.5×1088760107,589 km/hv = \frac{2 \times 3.14159 \times 1.5 \times 10^8}{8760} \approx 107,589 \text{ km/h}.

The Earth, Moon, and Sun Cycles - Revision Notes & Key Formulas | IGCSE Grade 7 Science