krit.club logo

Chemistry - Properties of Materials

Grade 7Cambridge (IGCSE)

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

The Particle Theory of Matter states that all matter is composed of tiny particles. The arrangement and energy of these particles define the state: Solid, Liquid, or Gas.

•

Physical properties are characteristics that can be observed without changing the substance's identity, such as density, melting pointmelting\ point, boiling pointboiling\ point, and electrical conductivity.

•

Density is the mass per unit volume of a substance. It is a constant for a pure substance at a given temperature and is expressed as ρ=mV\rho = \frac{m}{V}.

•

Metals are typically shiny (lustrouslustrous), malleablemalleable (can be hammered into sheets), ductileductile (can be drawn into wires), and are excellent conductors of heat and electricity.

•

Non-metals are generally brittlebrittle when solid, have lower melting pointsmelting\ points compared to metals, and act as electrical and thermal insulators.

•

Chemical properties describe how a substance reacts with others. For example, the reaction of Magnesium with Oxygen: 2Mg+O2→2MgO2Mg + O_2 \rightarrow 2MgO.

•

Solubility refers to the ability of a solute to dissolve in a solvent. Factors affecting solubility include temperature and the nature of the solutesolute and solventsolvent.

📐Formulae

ρ=mV\rho = \frac{m}{V}

m=ρ×Vm = \rho \times V

V=mρV = \frac{m}{\rho}

Volumerectangular prism=l×w×hVolume_{rectangular\ prism} = l \times w \times h

💡Examples

Problem 1:

A block of unknown metal has a mass of 405g405g and a volume of 150cm3150cm^3. Calculate its density and identify if it could be Aluminum (Density of Aluminum is 2.7g/cm32.7g/cm^3).

Solution:

ρ=405g150cm3=2.7g/cm3\rho = \frac{405g}{150cm^3} = 2.7g/cm^3

Explanation:

By dividing the mass (405g405g) by the volume (150cm3150cm^3), we get a density of 2.7g/cm32.7g/cm^3. Since this matches the known density of Aluminum, the metal is likely Aluminum.

Problem 2:

Describe the change in particle behavior when ice (H2O(s)H_2O(s)) is heated to become liquid water (H2O(l)H_2O(l)).

Solution:

The particles gain kinetic energykinetic\ energy, vibrate more vigorously, and eventually overcome the strong forces of attraction holding them in a fixed latticelattice.

Explanation:

In a solid, particles are in a fixed arrangement. Heating provides energy, allowing particles to slide past one another in the liquid state, though they remain close together.

Problem 3:

An object has a density of 0.8g/cm30.8g/cm^3. If it is placed in a container of water (density 1.0g/cm31.0g/cm^3), will it sink or float?

Solution:

The object will float.

Explanation:

An object floats if its density is less than the density of the fluid it is placed in. Since 0.8g/cm3<1.0g/cm30.8g/cm^3 < 1.0g/cm^3, the object is buoyant.

Properties of Materials Grade 7 Notes & Examples