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Chemistry - Elements, Compounds, and Mixtures

Grade 7IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

An Element is a pure substance that consists of only one type of atom and cannot be broken down into simpler substances by chemical means. For example, Iron (FeFe) and Oxygen (O2O_2).

A Compound is a substance formed when two or more different elements are chemically bonded together in a fixed ratio. Examples include Water (H2OH_2O) and Sodium Chloride (NaClNaCl).

A Mixture consists of two or more substances (elements or compounds) that are physically mixed but not chemically combined. The components retain their individual properties and can be separated by physical methods like filtration or distillation.

Molecules can be elements (e.g., O3O_3, P4P_4) if they contain only one type of atom, or compounds (e.g., CH4CH_4) if they contain different types of atoms.

Compounds have a fixed composition by mass, represented by a chemical formula like CO2CO_2, whereas mixtures can have varying compositions, such as air (mostly N2N_2 and O2O_2).

Pure substances (elements and compounds) have sharp, specific melting and boiling points, while mixtures melt or boil over a range of temperatures.

Chemical symbols represent elements (e.g., MgMg for Magnesium), and chemical formulae represent the number of atoms of each element in a unit of a substance (e.g., H2SO4H_2SO_4 contains 22 Hydrogen, 11 Sulfur, and 44 Oxygen atoms).

📐Formulae

A+BAB (Formation of a compound from elements)A + B \rightarrow AB \text{ (Formation of a compound from elements)}

Percentage of element=Mass of element in formulaTotal mass of compound×100%\text{Percentage of element} = \frac{\text{Mass of element in formula}}{\text{Total mass of compound}} \times 100\%

2H2(g)+O2(g)2H2O(l)2H_2(g) + O_2(g) \rightarrow 2H_2O(l)

Fe(s)+S(s)ΔFeS(s)Fe(s) + S(s) \xrightarrow{\Delta} FeS(s)

💡Examples

Problem 1:

Identify the number of atoms of each element present in one molecule of Glucose, C6H12O6C_6H_{12}O_6.

Solution:

C=6C = 6, H=12H = 12, O=6O = 6

Explanation:

The subscripts in the chemical formula C6H12O6C_6H_{12}O_6 indicate that there are 66 atoms of Carbon, 1212 atoms of Hydrogen, and 66 atoms of Oxygen chemically bonded together.

Problem 2:

Classify the following as an element, compound, or mixture: (a) Helium gas (HeHe), (b) Carbon dioxide (CO2CO_2), (c) Saltwater.

Solution:

(a) Element, (b) Compound, (c) Mixture

Explanation:

Helium (HeHe) consists of only one type of atom. Carbon dioxide (CO2CO_2) consists of two elements chemically bonded in a 1:21:2 ratio. Saltwater is a physical blend of NaClNaCl and H2OH_2O that can be separated by evaporation.

Problem 3:

How many total atoms are in a single unit of Magnesium Nitrate, Mg(NO3)2Mg(NO_3)_2?

Solution:

1+(1×2)+(3×2)=91 + (1 \times 2) + (3 \times 2) = 9 atoms

Explanation:

In Mg(NO3)2Mg(NO_3)_2, there is 11 Magnesium (MgMg) atom. The subscript 22 outside the parentheses multiplies everything inside: 1×2=21 \times 2 = 2 Nitrogen (NN) atoms and 3×2=63 \times 2 = 6 Oxygen (OO) atoms. Total = 1+2+6=91 + 2 + 6 = 9.