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Atomic Structure - Valency

Grade 7ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Valency is defined as the combining capacity of an atom of an element with other atoms to form molecules.

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The electrons present in the outermost shell of an atom are called valence electrons. These electrons determine the valency of the element.

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The Octet Rule states that atoms tend to gain, lose, or share electrons to achieve a stable configuration of 88 electrons in their outermost shell (or 22 in the case of the KK shell, known as a duplet).

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Metals typically have 11, 22, or 33 valence electrons and lose them to achieve stability, forming positively charged ions called cationscations.

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Non-metals typically have 55, 66, or 77 valence electrons and gain electrons to achieve stability, forming negatively charged ions called anionsanions.

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Noble gases like Helium (HeHe), Neon (NeNe), and Argon (ArAr) have a valency of 00 because their outermost shells are completely filled.

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Variable Valency: Some elements, particularly transition metals, exhibit more than one valency. For example, Iron (FeFe) can show valencies of 22 (FerrousFerrous) and 33 (FerricFerric).

📐Formulae

Valency (for metals)=Number of valence electrons (if 1,2, or 3)\text{Valency (for metals)} = \text{Number of valence electrons (if } 1, 2, \text{ or } 3)

Valency (for non-metals)=8−(Number of valence electrons)\text{Valency (for non-metals)} = 8 - (\text{Number of valence electrons})

Maximum electrons in a shell=2n2\text{Maximum electrons in a shell} = 2n^2

💡Examples

Problem 1:

Determine the valency of Magnesium (MgMg) with atomic number 1212.

Solution:

The electronic configuration is (2,8,2)(2, 8, 2). Since it has 22 valence electrons, its valency is 22.

Explanation:

Magnesium loses 22 electrons to achieve a stable octet, forming Mg2+Mg^{2+}. Since it loses 22 electrons, its combining capacity or valency is 22.

Problem 2:

Calculate the valency of Oxygen (OO) with atomic number 88.

Solution:

The electronic configuration is (2,6)(2, 6). Valency =8−6=2= 8 - 6 = 2.

Explanation:

Oxygen has 66 valence electrons. To complete its octet, it needs to gain 22 electrons. Therefore, its valency is 22.

Problem 3:

Find the valency of Chlorine (ClCl) with atomic number 1717.

Solution:

The electronic configuration is (2,8,7)(2, 8, 7). Valency =8−7=1= 8 - 7 = 1.

Explanation:

Chlorine has 77 electrons in its outermost shell. It gains 11 electron to reach a stable configuration of 88, so its valency is 11.