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The Ever-Evolving World of Science - Happy Exploring!

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Science is the systematic study of the structure and behavior of the physical and natural world through observation and experimentation. The process involves identifying a problem, forming a hypothesis, conducting experiments, and drawing conclusions.

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Measurement is a fundamental part of science. The International System of Units (SI) ensures consistency. Fundamental units include length in meters (m)meters\ (m), mass in kilograms (kg)kilograms\ (kg), and time in seconds (s)seconds\ (s).

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Motion is defined as the change in position of an object with respect to time. It can be uniform (constant speed) or non-uniform (changing speed).

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Speed is a scalar quantity representing the distance covered per unit of time, calculated as Speed=DistanceTimeSpeed = \frac{Distance}{Time}.

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Heat is a form of energy that flows from a body at a higher temperature to a body at a lower temperature. Temperature is the degree of hotness or coldness, measured using a thermometer in units like Celsius (∘C)Celsius\ (^{\circ}C), Fahrenheit (∘F)Fahrenheit\ (^{\circ}F), or Kelvin (K)Kelvin\ (K).

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In chemistry, substances are classified based on their composition into elements, compounds, and mixtures. A chemical formula like H2OH_{2}O represents the proportion of atoms in a molecule.

📐Formulae

Speed(v)=Distance(s)Time(t)Speed (v) = \frac{Distance (s)}{Time (t)}

Average Speed=Total Distance TraveledTotal Time TakenAverage\ Speed = \frac{Total\ Distance\ Traveled}{Total\ Time\ Taken}

C5=F−329\frac{C}{5} = \frac{F - 32}{9}

T(K)=T(∘C)+273.15T(K) = T(^{\circ}C) + 273.15

💡Examples

Problem 1:

A cyclist covers a distance of 100 meters100\ meters in 20 seconds20\ seconds. Calculate the speed of the cyclist.

Solution:

v=100 m20 s=5 m/sv = \frac{100\ m}{20\ s} = 5\ m/s

Explanation:

To find the speed, we divide the total distance (100 m100\ m) by the time taken (20 s20\ s), resulting in 5 meters per second5\ meters\ per\ second.

Problem 2:

Convert the human body temperature of 37∘C37^{\circ}C into Fahrenheit.

Solution:

375=F−329  ⟹  7.4×9=F−32  ⟹  66.6+32=98.6∘F\frac{37}{5} = \frac{F - 32}{9} \implies 7.4 \times 9 = F - 32 \implies 66.6 + 32 = 98.6^{\circ}F

Explanation:

Using the relationship between Celsius and Fahrenheit, we substitute C=37C = 37 into the formula C5=F−329\frac{C}{5} = \frac{F - 32}{9} and solve for FF.

Problem 3:

A scientist measures two liquid volumes in a lab: 450 ml450\ ml and 375 ml375\ ml. Find the total volume using vertical addition.

Solution:

450+375825\begin{array}{r} 450 \\ + 375 \\ \hline 825 \end{array}

Explanation:

By aligning the digits in their respective place values (units, tens, hundreds) and adding them, we find the total volume is 825 ml825\ ml.