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Energy - Thermal Energy and Heat Transfer

Grade 6IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Thermal energy is the total internal energy of an object due to the kinetic energy of its atoms and molecules, measured in Joules (JJ).

Temperature is a measure of the average kinetic energy of the particles in a substance, typically measured in degrees Celsius (C^\circ C) or Kelvin (KK).

Heat is the flow of thermal energy from a high-temperature object to a low-temperature object until thermal equilibrium is reached.

Conduction is the transfer of heat through direct contact in solids. Metals are excellent conductors because they contain 'free' electrons that transfer energy quickly.

Convection is the transfer of heat in fluids (liquids and gases). As a fluid is heated, it expands, becomes less dense, and rises, while cooler, denser fluid sinks, creating a convection current.

Radiation (Infrared) is the transfer of energy via electromagnetic waves. Unlike conduction and convection, radiation does not require a medium and can travel through a vacuum (e.g., from the Sun to Earth).

Thermal insulators are materials like wood, plastic, and air that are poor conductors of heat and are used to reduce energy transfer.

The change in temperature (ΔT\Delta T) depends on the mass (mm) of the substance and the specific heat capacity (cc).

📐Formulae

Q=mcΔTQ = mc\Delta T

ΔT=TfinalTinitial\Delta T = T_{final} - T_{initial}

Density(ρ)=mVDensity (\rho) = \frac{m}{V}

💡Examples

Problem 1:

A block of iron with a mass of 2 kg2\text{ kg} is heated from 20C20^\circ C to 50C50^\circ C. Calculate the change in temperature (ΔT\Delta T).

Solution:

ΔT=50C20C=30C\Delta T = 50^\circ C - 20^\circ C = 30^\circ C

Explanation:

To find the change in temperature, we subtract the initial temperature from the final temperature.

Problem 2:

Why does the handle of a metal spoon become hot when placed in a bowl of 100C100^\circ C soup?

Solution:

Thermal energy is transferred via conduction.

Explanation:

The fast-vibrating particles in the hot soup collide with the particles at the base of the metal spoon. This kinetic energy is passed from atom to atom along the handle until the entire spoon reaches a higher temperature.

Problem 3:

Calculate the heat energy (QQ) required to raise the temperature of 0.5 kg0.5\text{ kg} of water by 10C10^\circ C. (Specific heat capacity of water c=4200 J/kgCc = 4200\text{ J/kg}^\circ C).

Solution:

Q=0.5 kg×4200 J/kgC×10C=21,000 JQ = 0.5\text{ kg} \times 4200\text{ J/kg}^\circ C \times 10^\circ C = 21,000\text{ J}

Explanation:

Using the formula Q=mcΔTQ = mc\Delta T, we multiply the mass, the specific heat capacity, and the temperature change to find the total energy in Joules (JJ).

Thermal Energy and Heat Transfer - Revision Notes & Key Formulas | IGCSE Grade 6 Science