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Earth and Space - Stars and Galaxies

Grade 6IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A star is a massive sphere of plasma held together by its own gravity, primarily composed of Hydrogen (HH) and Helium (HeHe).

Stars produce energy through the process of nuclear fusion, where Hydrogen nuclei fuse to form Helium, releasing energy in the form of light and heat.

The Sun is a medium-sized star located at the center of our solar system. Its average distance from Earth is approximately 1.5×108 km1.5 \times 10^8 \text{ km}, which is defined as 11 Astronomical Unit (AUAU).

A Light Year (lyly) is a unit of distance used in astronomy. It represents the distance that light travels in a vacuum in one year, approximately 9.46×1012 km9.46 \times 10^{12} \text{ km}.

Galaxies are giant collections of stars, planetary systems, gas, and dust. Our solar system is located in a spiral galaxy called the Milky Way, which contains over 2×10112 \times 10^{11} stars.

The color of a star is an indicator of its surface temperature. Blue stars are the hottest (temperature >30,000 K> 30,000 \text{ K}), while red stars are the coolest (temperature 3,000 K\approx 3,000 \text{ K}).

📐Formulae

Distance=Speed of Light(c)×Time(t)\text{Distance} = \text{Speed of Light} (c) \times \text{Time} (t) sentiment

1 ly9,460,000,000,000 km=9.46×1012 km1 \text{ ly} \approx 9,460,000,000,000 \text{ km} = 9.46 \times 10^{12} \text{ km}

1 AU150,000,000 km=1.5×108 km1 \text{ AU} \approx 150,000,000 \text{ km} = 1.5 \times 10^8 \text{ km}

💡Examples

Problem 1:

If a star is located 1010 light years away from Earth, how many kilometers away is it? Express your answer in scientific notation.

Solution:

9.46×1013 km9.46 \times 10^{13} \text{ km}

Explanation:

Using the formula for 1 ly=9.46×1012 km1 \text{ ly} = 9.46 \times 10^{12} \text{ km}, we multiply by 1010. (9.46×1012)×10=9.46×1013 km(9.46 \times 10^{12}) \times 10 = 9.46 \times 10^{13} \text{ km}.

Problem 2:

Light from the Sun takes approximately 500500 seconds to reach Earth. Given the speed of light is 3×105 km/s3 \times 10^5 \text{ km/s}, calculate the distance to the Sun.

Solution:

1.5×108 km1.5 \times 10^8 \text{ km}

Explanation:

Distance is calculated as speed×time\text{speed} \times \text{time}. So, 3×105 km/s×500 s=150,000,000 km=1.5×108 km3 \times 10^5 \text{ km/s} \times 500 \text{ s} = 150,000,000 \text{ km} = 1.5 \times 10^8 \text{ km}.

Problem 3:

A student observes two stars, Star A (Blue) and Star B (Red). Which star has a higher surface temperature?

Solution:

Star A (Blue)

Explanation:

In astronomy, blue light has a shorter wavelength and higher energy, corresponding to higher surface temperatures, whereas red light indicates lower surface temperatures.

Stars and Galaxies - Revision Notes & Key Formulas | IGCSE Grade 6 Science