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Cells and Living Things - Using a Microscope

Grade 6IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Light Microscope is the primary tool used in biology to observe cells. It uses visible light and lenses to magnify specimens.

Total Magnification is the result of the combined power of the eyepiece lens and the objective lens. It is calculated as: Total Magnification=Eyepiece Power×Objective PowerTotal\ Magnification = Eyepiece\ Power \times Objective\ Power.

The Magnification Triangle (I=A×MI = A \times M) is used to calculate the relationship between the Image size (II), Actual size (AA), and Magnification (MM).

Units of measurement: Biological specimens are often measured in micrometers (μm\mu m). 1 mm=1000 μm1\ mm = 1000\ \mu m. To convert from mmmm to μm\mu m, multiply by 10310^3.

Resolution is the ability to distinguish between two separate points. Higher resolution allows for more detail to be seen under the microscope.

Staining is a technique used to make cell structures more visible. Common stains include iodine for plant cells and methylene blue for animal cells.

📐Formulae

Total Magnification=Eyepiece Magnification×Objective MagnificationTotal\ Magnification = Eyepiece\ Magnification \times Objective\ Magnification

Magnification (M)=Image Size (I)Actual Size (A)Magnification\ (M) = \frac{Image\ Size\ (I)}{Actual\ Size\ (A)}

Actual Size (A)=Image Size (I)Magnification (M)Actual\ Size\ (A) = \frac{Image\ Size\ (I)}{Magnification\ (M)}

1 mm=1000 μm1\ mm = 1000\ \mu m

💡Examples

Problem 1:

A student uses an eyepiece with 10×10\times magnification and an objective lens with 40×40\times magnification. What is the total magnification?

Solution:

10×40=400×10 \times 40 = 400\times

Explanation:

To find the total magnification, multiply the power of the eyepiece lens by the power of the objective lens currently in use.

Problem 2:

A cell in a textbook diagram has an image size (II) of 30 mm30\ mm. The magnification (MM) is stated as 500×500\times. Calculate the actual size (AA) of the cell in mmmm.

Solution:

A=30 mm500=0.06 mmA = \frac{30\ mm}{500} = 0.06\ mm

Explanation:

Using the formula A=IMA = \frac{I}{M}, divide the measured image size by the magnification factor.

Problem 3:

Convert the actual size of the cell from the previous example (0.06 mm0.06\ mm) into micrometers (μm\mu m).

Solution:

0.06 mm×1000=60 μm0.06\ mm \times 1000 = 60\ \mu m

Explanation:

Since 1 mm=1000 μm1\ mm = 1000\ \mu m, multiply the value in millimeters by 10001000 to get the size in micrometers.

Using a Microscope - Revision Notes & Key Formulas | IGCSE Grade 6 Science