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Simple Machines - Inclined Plane

Grade 6ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

An inclined plane is a simple machine consisting of a sloping surface that connects a lower level to a higher level, used to lift heavy loads with less effort.

It acts as a force multiplier. The effort (EE) is applied along the slope, while the load (LL) is lifted vertically to a height (hh).

The Mechanical Advantage (MAMA) of an inclined plane is always greater than 11 because the length of the slope (LL) is always greater than the vertical height (hh).

As the angle of inclination decreases (making the slope gentler), the length of the plane increases, which increases the MAMA and reduces the effort required.

Real-world applications include ramps in hospitals, sloping roads on hills, staircases, and gangways of ships.

A winding road on a mountain is an example of an inclined plane that increases the distance of travel to reduce the effort needed by vehicles to climb steep heights.

📐Formulae

Mechanical Advantage (MA)=Length of the Plane (l)Vertical Height of the Plane (h)\text{Mechanical Advantage (MA)} = \frac{\text{Length of the Plane (l)}}{\text{Vertical Height of the Plane (h)}}

Mechanical Advantage (MA)=Load (L)Effort (E)\text{Mechanical Advantage (MA)} = \frac{\text{Load (L)}}{\text{Effort (E)}}

Work Done=Force×Distance\text{Work Done} = \text{Force} \times \text{Distance}

Effort (E)=Load (L)MA\text{Effort (E)} = \frac{\text{Load (L)}}{\text{MA}}

💡Examples

Problem 1:

A wooden plank 4 m4\text{ m} long is used to push a drum onto a truck platform which is 1 m1\text{ m} high. Calculate the Mechanical Advantage (MAMA) of this inclined plane.

Solution:

Given: Length of plane (ll) = 4 m4\text{ m}, Height (hh) = 1 m1\text{ m}. Using the formula MA=lhMA = \frac{l}{h}, we get MA=4 m1 m=4MA = \frac{4\text{ m}}{1\text{ m}} = 4.

Explanation:

The MAMA is 44, which means the machine multiplies the applied effort by 44 times.

Problem 2:

A load of 600 N600\text{ N} is pushed up a ramp of length 5 m5\text{ m} and height 2 m2\text{ m}. Calculate the effort required, assuming no friction.

Solution:

Step 1: Calculate MA=lh=52=2.5MA = \frac{l}{h} = \frac{5}{2} = 2.5. Step 2: Use MA=LEMA = \frac{L}{E} to find Effort. 2.5=600EE=6002.5=240 N2.5 = \frac{600}{E} \Rightarrow E = \frac{600}{2.5} = 240\text{ N}.

Explanation:

By using the inclined plane, an effort of only 240 N240\text{ N} is needed to lift a load of 600 N600\text{ N}.

Problem 3:

Why is it easier to walk up a longer, gentler slope than a shorter, steeper one to reach the same height?

Solution:

A longer slope has a greater length (ll) for the same height (hh). Since MA=lhMA = \frac{l}{h}, the MAMA increases as ll increases.

Explanation:

According to the principle of simple machines, a higher MAMA requires less effort. Even though the distance walked is more, the force required from our legs is significantly reduced.

Inclined Plane - Revision Notes & Key Formulas | ICSE Class 6 Science