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Physical Quantities and Measurement - Measurement of Temperature

Grade 6ICSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Temperature is defined as the degree of hotness or coldness of an object.

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The S.I. unit of temperature is Kelvin (KK), but it is commonly measured in degree Celsius (∘C^\circ C) and degree Fahrenheit (∘F^\circ F).

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A thermometer is a device used to measure temperature, working on the principle of thermal expansion of liquids.

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Mercury and Alcohol are commonly used thermometric liquids because they expand uniformly with heat.

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The Clinical Thermometer is used to measure human body temperature. It has a range from 35∘C35^\circ C to 42∘C42^\circ C (or 95∘F95^\circ F to 108∘F108^\circ F) and contains a 'kink' or constriction to prevent the mercury level from falling immediately.

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The Laboratory Thermometer is used for scientific purposes with a typical range from βˆ’10∘C-10^\circ C to 110∘C110^\circ C. It does not have a kink.

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The normal temperature of a healthy human body is 37∘C37^\circ C or 98.6∘F98.6^\circ F.

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The lower fixed point is the melting point of pure ice (0∘C0^\circ C or 32∘F32^\circ F), and the upper fixed point is the boiling point of pure water (100∘C100^\circ C or 212∘F212^\circ F).

πŸ“Formulae

F=(95Γ—C)+32F = \left( \frac{9}{5} \times C \right) + 32

C=59Γ—(Fβˆ’32)C = \frac{5}{9} \times (F - 32)

K=C+273K = C + 273

πŸ’‘Examples

Problem 1:

Convert 40∘C40^\circ C into the Fahrenheit scale.

Solution:

F=(95Γ—40)+32=(9Γ—8)+32=72+32=104∘FF = \left( \frac{9}{5} \times 40 \right) + 32 = (9 \times 8) + 32 = 72 + 32 = 104^\circ F

Explanation:

Using the conversion formula, we multiply the Celsius value by 95\frac{9}{5} and then add 3232 to get the temperature in Fahrenheit.

Problem 2:

If a person has a fever of 102.2∘F102.2^\circ F, what is their temperature in ∘C^\circ C?

Solution:

C=59Γ—(102.2βˆ’32)=59Γ—70.2=5Γ—7.8=39∘CC = \frac{5}{9} \times (102.2 - 32) = \frac{5}{9} \times 70.2 = 5 \times 7.8 = 39^\circ C

Explanation:

Subtract 3232 from the Fahrenheit value first, then multiply the result by 59\frac{5}{9} to find the Celsius equivalent.

Problem 3:

Convert the boiling point of water (100∘C100^\circ C) to the Kelvin scale.

Solution:

K=100+273=373KK = 100 + 273 = 373 K

Explanation:

To convert Celsius to Kelvin, we add 273273 to the Celsius temperature. Note that the unit Kelvin does not use the degree symbol.

Measurement of Temperature - Revision Notes & Key Formulas | ICSE Class 6 Science