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Human Body - The Respiratory System

Grade 6ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Respiration is a biochemical process where food (glucose) is oxidized to release energy in the form of ATP. The general equation is C6H12O6+6O2→6CO2+6H2O+EnergyC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy}.

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Breathing is the physical process of inhaling air rich in O2O_2 and exhaling air rich in CO2CO_2.

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The human respiratory tract consists of the nostrils, nasal cavity, pharynx, larynx, trachea, bronchi, bronchioles, and alveoli.

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The trachea or windpipe is held open by 'C' shaped cartilaginous rings to prevent it from collapsing.

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Alveoli are tiny balloon-like structures where the actual exchange of gases (O2O_2 and CO2CO_2) takes place through the process of diffusion.

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The diaphragm is a large, dome-shaped muscular sheet that separates the thoracic cavity from the abdominal cavity.

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During inhalation, the diaphragm contracts and moves downwards, and the ribs move upwards and outwards, increasing the volume of the chest cavity and lowering the air pressure inside.

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During exhalation, the diaphragm relaxes and moves upwards, and the ribs move downwards and inwards, decreasing the volume and increasing the air pressure to push air out.

📐Formulae

C6H12O6+6O2→6CO2+6H2O+Energy (ATP)C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy (ATP)}

Breathing Rate=Total number of breathsTotal time in minutes\text{Breathing Rate} = \frac{\text{Total number of breaths}}{\text{Total time in minutes}}

💡Examples

Problem 1:

What happens when exhaled air is passed through lime water? Write the chemical notation for the change.

Solution:

The lime water turns milky.

Explanation:

Exhaled air contains a high concentration of CO2CO_2. When CO2CO_2 reacts with lime water (Ca(OH)2Ca(OH)_2), it forms an insoluble white precipitate of calcium carbonate (CaCO3CaCO_3), making the water appear milky: Ca(OH)2+CO2→CaCO3+H2OCa(OH)_2 + CO_2 \rightarrow CaCO_3 + H_2O.

Problem 2:

Calculate the breathing rate of a person who breathes 7575 times in 55 minutes.

Solution:

15 breaths/minute15 \text{ breaths/minute}

Explanation:

Using the formula Breathing Rate=Total breathsTotal time\text{Breathing Rate} = \frac{\text{Total breaths}}{\text{Total time}}, we get 755=15\frac{75}{5} = 15.

Problem 3:

Explain the role of O2O_2 in cellular respiration.

Solution:

Oxidation of Glucose.

Explanation:

In the presence of O2O_2, glucose (C6H12O6C_6H_{12}O_6) is broken down into CO2CO_2 and H2OH_2O to release the energy required for cellular activities.