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Elements, Compounds and Mixtures - Chemical Formulae of Compounds

Grade 6ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A Chemical Formula is a symbolic representation of one molecule of an element or a compound. It uses symbols of elements and numerical subscripts to show the proportion of atoms.

A Compound is a substance formed when two or more elements combine chemically in a fixed ratio by mass. For example, H2OH_2O always contains two atoms of Hydrogen for every one atom of Oxygen.

The Subscript in a formula (the small number written at the bottom right of a symbol) indicates the number of atoms of that specific element present in the molecule. If no number is written, it is assumed to be 11.

Atomicity refers to the total number of atoms present in one molecule of an element or compound. For example, the atomicity of Ozone (O3O_3) is 33.

In a chemical formula, the metal (or more electropositive element) is usually written first, followed by the non-metal. For example, in Sodium Chloride (NaClNaCl), Sodium (NaNa) is the metal.

📐Formulae

H2O (Water)H_2O \text{ (Water)}

CO2 (Carbon Dioxide)CO_2 \text{ (Carbon Dioxide)}

NaCl (Sodium Chloride - Common Salt)NaCl \text{ (Sodium Chloride - Common Salt)}

MgO (Magnesium Oxide)MgO \text{ (Magnesium Oxide)}

NH3 (Ammonia)NH_3 \text{ (Ammonia)}

CH4 (Methane)CH_4 \text{ (Methane)}

CaCO3 (Calcium Carbonate)CaCO_3 \text{ (Calcium Carbonate)}

HCl (Hydrochloric Acid)HCl \text{ (Hydrochloric Acid)}

💡Examples

Problem 1:

How many atoms of each element are present in a molecule of Sodium Carbonate (Na2CO3Na_2CO_3)?

Solution:

Sodium (NaNa) = 22 atoms, Carbon (CC) = 11 atom, Oxygen (OO) = 33 atoms.

Explanation:

The subscripts tell us the quantity: NaNa has a subscript of 22, CC has no subscript (which means 11), and OO has a subscript of 33.

Problem 2:

Calculate the total atomicity of a Glucose molecule, represented by the formula C6H12O6C_6H_{12}O_6.

Solution:

Atomicity = 6+12+6=246 + 12 + 6 = 24

Explanation:

To find the atomicity, we sum the number of atoms of all elements: 66 Carbon atoms + 1212 Hydrogen atoms + 66 Oxygen atoms = 2424 atoms.

Problem 3:

Write the chemical formula for a compound containing one atom of Magnesium and two atoms of Chlorine.

Solution:

MgCl2MgCl_2

Explanation:

We write the symbol for Magnesium (MgMg) first and Chlorine (ClCl) second. Since there are two Chlorine atoms, we add the subscript 22 to ClCl.

Chemical Formulae of Compounds - Revision Notes & Key Formulas | ICSE Class 6 Science