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Energy Forms and Transfers - Law of Conservation of Energy

Grade 6IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Energy is the capacity to do work and is measured in Joules (JJ).

The Law of Conservation of Energy states that energy cannot be created or destroyed; it can only be transformed from one form to another or transferred between objects.

The total energy in a closed system remains constant, expressed as Etotal=extconstantE_{total} = ext{constant}.

Kinetic Energy (EkE_k) is the energy possessed by an object due to its motion, depending on mass (mm) and velocity (vv).

Gravitational Potential Energy (EpE_p) is the energy stored in an object due to its height (hh) above a reference point.

Energy transfers involve energy moving from one place to another (e.g., heat moving from a stove to a pan), while energy transformations involve changing forms (e.g., Chemical Energy in a battery changing to Electrical Energy).

In real-world systems, energy is often 'dissipated' (usually as heat, QQ, or sound) due to friction, though the total energy still follows the law of conservation.

📐Formulae

Etotal=Ek+EpE_{total} = E_k + E_p

Ek=12mv2E_k = \frac{1}{2}mv^2

Ep=mghE_p = mgh

Einput=Eusefuloutput+EwastedoutputE_{input} = E_{useful\,output} + E_{wasted\,output}

Efficiency=Useful Energy OutputTotal Energy Input×100%Efficiency = \frac{\text{Useful Energy Output}}{\text{Total Energy Input}} \times 100\%

💡Examples

Problem 1:

A 2kg2\,kg ball is held at a height where it has 40J40\,J of Gravitational Potential Energy (EpE_p). If the ball is dropped, what is its Kinetic Energy (EkE_k) just before it hits the ground, assuming no air resistance?

Solution:

Ek=40JE_k = 40\,J

Explanation:

By the Law of Conservation of Energy, the initial energy at the top must equal the final energy at the bottom (Einitial=EfinalE_{initial} = E_{final}). Since all EpE_p is converted into EkE_k during the fall, the Kinetic Energy at the bottom is equal to the Potential Energy at the top.

Problem 2:

An electric motor is supplied with 200J200\,J of electrical energy. It performs 150J150\,J of useful mechanical work. Calculate the amount of energy dissipated as heat (QQ).

Solution:

Q=50JQ = 50\,J

Explanation:

Using the conservation formula Einput=Euseful+EwastedE_{input} = E_{useful} + E_{wasted}, we substitute the known values: 200J=150J+Q200\,J = 150\,J + Q. Subtracting 150J150\,J from both sides gives Q=50JQ = 50\,J.

Problem 3:

A swinging pendulum has 10J10\,J of EpE_p at its highest point. At its lowest point, it has 8J8\,J of EkE_k. How much energy was transformed into thermal energy due to air resistance?

Solution:

2J2\,J

Explanation:

The total energy at the start was 10J10\,J. At the bottom, the measurable mechanical energy is 8J8\,J. The 'missing' energy (10J8J=2J10\,J - 8\,J = 2\,J) has been transformed into heat (QQ) because energy must be conserved.

Law of Conservation of Energy - Revision Notes & Key Formulas | IB Grade 6 Science