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Cell Biology - Microscope Parts and Usage

Grade 6IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The compound light microscope is a fundamental tool in cell biology used to magnify small specimens like plant and animal cells using visible light and glass lenses.

The Eyepiece (Ocular Lens) is the part you look through, which typically has a magnification of 10×10\times.

Objective Lenses are the primary lenses used for magnification, usually found in three powers: Low (4×4\times), Medium (10×10\times), and High (40×40\times).

The Stage is the flat platform where the slide is placed, held in place by stage clips.

The Diaphragm (or Iris) controls the amount of light passing through the specimen to improve contrast.

The Coarse Adjustment Knob moves the stage significantly for initial focusing under low power, while the Fine Adjustment Knob is used for precise sharpening under high power.

Resolution is the ability of the microscope to distinguish between two separate points; higher resolution allows for clearer detail.

Biological specimens are often measured in micrometers (μm\mu m), where 1 mm=1000 μm1\ mm = 1000\ \mu m or 103 μm10^3\ \mu m.

📐Formulae

Total Magnification=Magnificationeyepiece×MagnificationobjectiveTotal\ Magnification = Magnification_{eyepiece} \times Magnification_{objective}

Actual Size=Image SizeMagnificationActual\ Size = \frac{Image\ Size}{Magnification}

1 mm=1000 μm1\ mm = 1000\ \mu m

💡Examples

Problem 1:

A student views a cheek cell using a 10×10\times eyepiece and a 40×40\times objective lens. What is the total magnification of the cell?

Solution:

400×400\times

Explanation:

To find the total magnification, multiply the magnification of the eyepiece by the magnification of the objective lens: 10×40=40010 \times 40 = 400.

Problem 2:

A specimen on a slide measures 0.2 mm0.2\ mm in real life. How many micrometers (μm\mu m) is this?

Solution:

200 μm200\ \mu m

Explanation:

Since 1 mm=1000 μm1\ mm = 1000\ \mu m, we multiply the measurement by 10001000: 0.2×1000=200 μm0.2 \times 1000 = 200\ \mu m.

Problem 3:

An image of a cell in a textbook is 20 mm20\ mm long. If the magnification used was 500×500\times, what is the actual size of the cell in mmmm?

Solution:

0.04 mm0.04\ mm

Explanation:

Using the formula Actual Size=Image SizeMagnificationActual\ Size = \frac{Image\ Size}{Magnification}, we calculate 20 mm500=0.04 mm\frac{20\ mm}{500} = 0.04\ mm.

Microscope Parts and Usage - Revision Notes & Key Formulas | IB Grade 6 Science