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Living Things - Plant and Animal Adaptations

Grade 5IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Adaptation is the biological process where organisms evolve features to survive in their environment. These are categorized into structural (physical features) and behavioral (actions).

Plants perform photosynthesis to create food, represented by the chemical equation: 6CO2+6H2O+light energyC6H12O6+6O26CO_2 + 6H_2O + \text{light energy} \rightarrow C_6H_{12}O_6 + 6O_2.

Xerophytes are plants adapted to dry environments. They often have thick waxy cuticles and spines instead of leaves to reduce the loss of H2OH_2O via transpiration.

Hydrophytes are aquatic plants that have large air spaces to stay afloat and facilitate the exchange of gases like O2O_2 and CO2CO_2.

The Surface Area to Volume ratio (SA:VSA:V) is a crucial adaptation factor. Animals in cold climates often have smaller ears and tails to decrease the surface area available for heat loss.

Camouflage and mimicry are structural adaptations that help organisms avoid predators or sneak up on prey by blending into their surroundings.

Hibernation is a behavioral adaptation where an animal's metabolic rate drops significantly, reducing the need for energy (glucose, C6H12O6C_6H_{12}O_6) during cold months.

📐Formulae

6CO2+6H2O+lightC6H12O6+6O26CO_2 + 6H_2O + \text{light} \rightarrow C_6H_{12}O_6 + 6O_2

C6H12O6+6O26CO2+6H2O+Energy (ATP)C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy (ATP)}

Surface Area to Volume Ratio=SAV\text{Surface Area to Volume Ratio} = \frac{SA}{V}

Tchange1MassT_{change} \propto \frac{1}{\text{Mass}} (Simplified heat loss concept)

💡Examples

Problem 1:

A desert plant has a thick, fleshy stem. If the stem stores 500500 mL of H2OH_2O and loses 22 mL per day through transpiration, how long can it survive without rain?

Solution:

500 mL2 mL/day=250 days\frac{500\text{ mL}}{2\text{ mL/day}} = 250\text{ days}

Explanation:

Succulent stems are structural adaptations for water storage in arid biomes where H2OH_2O is scarce.

Problem 2:

Explain why a Polar Bear has a small surface area to volume ratio (SA:VSA:V) compared to a Fennec Fox.

Solution:

A smaller SA:VSA:V ratio minimizes the area exposed to the cold, reducing heat loss.

Explanation:

Because heat loss occurs at the surface, larger, rounder bodies (lower SA:VSA:V) retain internal thermal energy more efficiently in temperatures below 0C0^{\circ}C.

Problem 3:

Identify the gas released by plants during the day that is essential for animal survival.

Solution:

O2O_2 (Oxygen)

Explanation:

During photosynthesis, plants take in CO2CO_2 and release O2O_2 as a byproduct, which animals use for cellular respiration.

Plant and Animal Adaptations - Revision Notes & Key Formulas | IB Grade 5 Science