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The Amazing World of Solutes, Solvents, and Solutions - Factors Affecting Dissolution

Grade 5CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A solution is a homogeneous mixture formed when a substance (solute) is dissolved in another substance (solvent). The relationship is expressed as: Solute+Solvent=SolutionSolute + Solvent = Solution.

Solute: The substance that gets dissolved (e.g., salt NaClNaCl or sugar C12H22O11C_{12}H_{22}O_{11}).

Solvent: The medium in which the solute dissolves (e.g., water H2OH_2O). Water is known as the 'Universal Solvent'.

Temperature: Dissolution happens faster at higher temperatures. Heating the solvent (H2OH_2O) increases the kinetic energy of its molecules, allowing them to break down solute particles more rapidly.

Stirring/Agitation: Stirring helps the solute particles spread quickly through the solvent, bringing fresh solvent molecules into contact with the solute.

Particle Size (Surface Area): Smaller particles (like powdered sugar) dissolve faster than large chunks (like sugar cubes) because more surface area is exposed to the solvent molecules.

Saturated Solution: A solution in which no more solute can be dissolved at a given temperature.

📐Formulae

Solute+Solvent=SolutionSolute + Solvent = Solution

Rate of DissolutionTemperature\text{Rate of Dissolution} \propto \text{Temperature}

Rate of Dissolution1Particle Size\text{Rate of Dissolution} \propto \frac{1}{\text{Particle Size}}

Concentration=Mass of SoluteVolume of Solution\text{Concentration} = \frac{\text{Mass of Solute}}{\text{Volume of Solution}}

💡Examples

Problem 1:

Why does a teaspoon of salt (NaClNaCl) dissolve faster in a glass of hot water (H2OH_2O) compared to a glass of cold water?

Solution:

The rate of dissolution is higher in hot water due to increased thermal energy.

Explanation:

In hot H2OH_2O, the molecules move with higher speed and hit the NaClNaCl crystals with more force and frequency, breaking the ionic bonds faster than in cold water.

Problem 2:

If you have 10g of sugar crystals and 10g of powdered sugar, which one will form a solution in H2OH_2O first?

Solution:

The powdered sugar will dissolve faster.

Explanation:

Powdered sugar has a much larger total surface area compared to large crystals. This allows more H2OH_2O molecules to surround and interact with the sugar molecules (C12H22O11C_{12}H_{22}O_{11}) simultaneously.

Problem 3:

What happens to the solubility of sugar in water if you keep adding sugar until it starts settling at the bottom?

Solution:

The solution becomes a 'Saturated Solution'.

Explanation:

When the solvent molecules (H2OH_2O) are completely occupied holding solute particles, no more space is available for additional solute. This state is called saturation.

Factors Affecting Dissolution - Revision Notes & Key Formulas | CBSE Class 5 Science