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Force, Work, and Energy - Simple Machines in Daily Life

Grade 4CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Force: A push or pull acting on an object. It can change the shape, size, speed, or direction of an object. Force is measured in Newtons (NN).

Work: In science, work is said to be done when a force applied to an object causes it to move a certain distance in the direction of the force. If the object does not move, work done is 00.

Energy: The ability or capacity to do work. Common forms include Solar energy, Wind energy, and Heat energy.

Simple Machines: Tools that make our work easier and faster by changing the direction or amount of force required. There are six main types: Lever, Pulley, Wheel and Axle, Inclined Plane, Screw, and Wedge.

Lever: A stiff rod that turns around a fixed point called the Fulcrum. Examples include scissors and see-saws.

Inclined Plane: A sloping surface used to move heavy loads to a higher level with less effort, such as a ramp or a slide.

Pulley: A simple machine consisting of a wheel with a groove for a rope, used to lift heavy objects like a bucket from a well.

Wedge: A tool with at least one slanting side ending in a sharp edge, used to cut or split objects (e.g., an axe or a knife).

📐Formulae

Work=Force×DistanceWork = Force \times Distance

W=F×dW = F \times d

Work (if no movement)=Force×0=0Work \text{ (if no movement)} = Force \times 0 = 0

💡Examples

Problem 1:

Rohan pushes a heavy table with a force of 20 N20\ N, but the table does not move at all. How much work has Rohan done?

Solution:

Work=0 JoulesWork = 0\ Joules

Explanation:

Since the distance (dd) moved by the table is 0 m0\ m, the work done is calculated as W=20 N×0 m=0W = 20\ N \times 0\ m = 0. Work is only done when there is displacement.

Problem 2:

A laborer uses a force of 50 N50\ N to push a cart over a distance of 10 m10\ m. Calculate the work done.

Solution:

Work=500 JoulesWork = 500\ Joules

Explanation:

Using the formula Work=Force×DistanceWork = Force \times Distance, we get 50 N×10 m=500 J50\ N \times 10\ m = 500\ J.

Problem 3:

Identify the simple machine used in a bottle opener.

Solution:

Lever

Explanation:

A bottle opener acts as a lever where the handle provides the effort, the cap is the load, and the edge of the cap acts as the fulcrum.

Simple Machines in Daily Life - Revision Notes & Key Formulas | CBSE Class 4 Science