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Environment and Recreation - Games We Play: Sports and Recreation

Grade 3CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Recreation: Any activity done for enjoyment and relaxation when one is not working is called recreation. It helps to refresh our mind and body.

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Indoor Games: These are games played inside a room or a building. Examples include Chess, Ludo, and Carrom. They often require focus and mental strategy.

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Outdoor Games: These are played in open spaces like playgrounds or stadiums. Examples include Cricket, Football, and Hockey. These games involve significant physical exertion and use of energy (EE).

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Individual vs. Team Games: Some games are played alone (like swimming or cycling), while others are played in groups. Team games foster cooperation and team spirit.

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Rules of the Game: Every game has a set of rules that players must follow. This ensures fair play and prevents disputes.

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Friction in Games: In games like Carrom, we use powder to reduce friction (μ\mu). This allows the striker to move smoothly across the board.

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Energy and Sports: Playing games requires kinetic energy (K.E.=12mv2K.E. = \frac{1}{2}mv^2) which comes from the food we eat.

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Local/Traditional Games: These are games passed down through generations, such as Kabaddi, Kho-kho, and Gilli-danda.

📐Formulae

Speed(v)=Distance(d)Time(t)Speed (v) = \frac{Distance (d)}{Time (t)}

Force(F)=m×aForce (F) = m \times a

Pressure(P)=Force(F)Area(A)Pressure (P) = \frac{Force (F)}{Area (A)}

Work Done(W)=F×d\text{Work Done} (W) = F \times d

💡Examples

Problem 1:

Why does a striker move further on a carrom board when powder is sprinkled on it?

Solution:

Sprinkling powder reduces the friction (μ\mu).

Explanation:

Friction is the force that opposes motion. By adding powder, the surface becomes smoother, making the coefficient of friction μ\mu smaller, allowing the striker to travel a greater distance dd with the same force FF.

Problem 2:

If a child runs 100100 meters in 2020 seconds, what is their speed?

Solution:

v=5 m/sv = 5\text{ m/s}

Explanation:

Using the formula v=dtv = \frac{d}{t}, we substitute the values: v=10020=5v = \frac{100}{20} = 5. The speed is 55 meters per second.

Problem 3:

Why is air pumped into a football?

Solution:

To increase the internal air pressure (PP).

Explanation:

The air particles inside the ball push against the walls. According to P=FAP = \frac{F}{A}, the pressure makes the ball firm and allows it to bounce back (rebound) when it hits the ground.