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Environment and Recreation - Games We Play: Sports and Recreation

Grade 3CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Recreation: Any activity done for enjoyment and relaxation when one is not working is called recreation. It helps to refresh our mind and body.

Indoor Games: These are games played inside a room or a building. Examples include Chess, Ludo, and Carrom. They often require focus and mental strategy.

Outdoor Games: These are played in open spaces like playgrounds or stadiums. Examples include Cricket, Football, and Hockey. These games involve significant physical exertion and use of energy (EE).

Individual vs. Team Games: Some games are played alone (like swimming or cycling), while others are played in groups. Team games foster cooperation and team spirit.

Rules of the Game: Every game has a set of rules that players must follow. This ensures fair play and prevents disputes.

Friction in Games: In games like Carrom, we use powder to reduce friction (μ\mu). This allows the striker to move smoothly across the board.

Energy and Sports: Playing games requires kinetic energy (K.E.=12mv2K.E. = \frac{1}{2}mv^2) which comes from the food we eat.

Local/Traditional Games: These are games passed down through generations, such as Kabaddi, Kho-kho, and Gilli-danda.

📐Formulae

Speed(v)=Distance(d)Time(t)Speed (v) = \frac{Distance (d)}{Time (t)}

Force(F)=m×aForce (F) = m \times a

Pressure(P)=Force(F)Area(A)Pressure (P) = \frac{Force (F)}{Area (A)}

Work Done(W)=F×d\text{Work Done} (W) = F \times d

💡Examples

Problem 1:

Why does a striker move further on a carrom board when powder is sprinkled on it?

Solution:

Sprinkling powder reduces the friction (μ\mu).

Explanation:

Friction is the force that opposes motion. By adding powder, the surface becomes smoother, making the coefficient of friction μ\mu smaller, allowing the striker to travel a greater distance dd with the same force FF.

Problem 2:

If a child runs 100100 meters in 2020 seconds, what is their speed?

Solution:

v=5 m/sv = 5\text{ m/s}

Explanation:

Using the formula v=dtv = \frac{d}{t}, we substitute the values: v=10020=5v = \frac{100}{20} = 5. The speed is 55 meters per second.

Problem 3:

Why is air pumped into a football?

Solution:

To increase the internal air pressure (PP).

Explanation:

The air particles inside the ball push against the walls. According to P=FAP = \frac{F}{A}, the pressure makes the ball firm and allows it to bounce back (rebound) when it hits the ground.

Games We Play: Sports and Recreation Revision - Class 3 Science CBSE