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Chemistry - Electrochemistry

Grade 10IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Electrolysis is the process of using electricity to break down ionic compounds into their constituent elements. The substance undergoing electrolysis must be in a molten or aqueous state, known as an electrolyteelectrolyte, so that ions are free to move.

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Electrodes: The positive electrode is the anodeanode, and the negative electrode is the cathodecathode. A common mnemonic is PANICPANIC: Positive Anode, Negative Is Cathode.

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Oxidation and Reduction: Oxidation occurs at the anode (loss of electrons), and reduction occurs at the cathode (gain of electrons). This is summarized by OILRIGOIL RIG: Oxidation Is Loss, Reduction Is Gain.

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Electrolysis of molten compounds: For example, in molten PbBr2PbBr_2, lead ions (Pb2+Pb^{2+}) are reduced to lead metal at the cathode, and bromide ions (Brβˆ’Br^-) are oxidized to bromine gas at the anode.

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Electrolysis of aqueous solutions: At the cathode, either the metal ion or H+H^+ is discharged. The less reactive species is discharged (usually H+H^+ unless the metal is below hydrogen in the reactivity series, like Cu2+Cu^{2+} or Ag+Ag^+).

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At the anode in aqueous solutions: Hydroxide ions (OHβˆ’OH^-) are discharged to form O2O_2 and H2OH_2O unless a high concentration of halide ions (Clβˆ’Cl^-, Brβˆ’Br^-, Iβˆ’I^-) is present.

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Electroplating: A process used to coat a metal object with a thin layer of another metal. The object to be plated is the cathode, the plating metal is the anode, and the electrolyte contains ions of the plating metal.

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Hydrogen Fuel Cells: These produce electricity from the reaction between hydrogen and oxygen. The overall reaction is 2H2(g)+O2(g)ightarrow2H2O(l)2H_2(g) + O_2(g) ightarrow 2H_2O(l), which is efficient and produces only water as a byproduct.

πŸ“Formulae

ightarrow X \text{ (Reduction at Cathode)}$$
ightarrow X + ne^- \text{ (Oxidation at Anode)}$$
ightarrow O_2 (g) + 2H_2O (l) + 4e^- \text{ (Discharge of hydroxide)}$$
ightarrow H_2 (g) \text{ (Discharge of hydrogen ions)}$$
ightarrow 2H_2O \text{ (Overall reaction in a fuel cell)}$$

πŸ’‘Examples

Problem 1:

Describe the electrolysis of concentrated aqueous sodium chloride (NaClNaCl), also known as brine.

Solution:

Cathode: 2H+(aq)+2eβˆ’ightarrowH2(g)2H^+ (aq) + 2e^- ightarrow H_2 (g); Anode: 2Clβˆ’(aq)ightarrowCl2(g)+2eβˆ’2Cl^- (aq) ightarrow Cl_2 (g) + 2e^-.

Explanation:

In aqueous NaClNaCl, both Na+Na^+, H+H^+, Clβˆ’Cl^-, and OHβˆ’OH^- ions are present. Hydrogen is less reactive than sodium, so H2H_2 gas is produced at the cathode. Because the solution is concentrated, Clβˆ’Cl^- is discharged at the anode instead of OHβˆ’OH^-, producing Cl2Cl_2 gas. The remaining Na+Na^+ and OHβˆ’OH^- ions form sodium hydroxide (NaOHNaOH).

Problem 2:

Write the half-equations for the electrolysis of molten aluminum oxide (Al2O3Al_2O_3) in the Hall-HΓ©roult process.

Solution:

Cathode: Al3++3eβˆ’ightarrowAlAl^{3+} + 3e^- ightarrow Al; Anode: 2O2βˆ’ightarrowO2+4eβˆ’2O^{2-} ightarrow O_2 + 4e^-.

Explanation:

Aluminium ions (Al3+Al^{3+}) move to the negative cathode where they gain electrons (reduction) to form liquid aluminium. Oxide ions (O2βˆ’O^{2-}) move to the positive anode where they lose electrons (oxidation) to form oxygen gas. Note: The oxygen reacts with the carbon anodes to form CO2CO_2, requiring them to be replaced regularly.

Electrochemistry - Revision Notes & Key Formulas | IGCSE Grade 10 Science