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Chemistry - Atoms, Elements and Compounds

Grade 10IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The atom consists of a central nucleus containing protons (p+p^+) and neutrons (n0n^0), surrounded by electrons (ee^-) orbiting in specific energy levels or shells.

Atomic number (ZZ) is the number of protons in the nucleus of an atom. The Mass number (AA) is the total number of protons and neutrons.

Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons, resulting in different mass numbers (e.g., 1735Cl^{35}_{17}Cl and 1737Cl^{37}_{17}Cl).

Relative Atomic Mass (ArA_r) is the average mass of naturally occurring atoms of an element on a scale where the 12C^{12}C atom has a mass of exactly 1212 units.

Elements are substances made of only one type of atom. Compounds are substances made of two or more elements chemically combined in fixed proportions, such as CO2CO_2 or NaClNaCl.

Mixtures contain two or more substances (elements or compounds) that are not chemically bonded and can be separated by physical means.

Electronic configuration follows a specific pattern: the first shell holds up to 22 electrons, the second holds up to 88, and the third holds up to 88 (for the first 20 elements). For example, Sodium (NaNa) is 2,8,12, 8, 1.

Noble gases (Group VIII/0) have a full outer shell of electrons (a stable octet), making them chemically unreactive.

Ionic bonding occurs through the transfer of electrons from a metal atom to a non-metal atom, resulting in the formation of positive cations (Mg2+Mg^{2+}) and negative anions (O2O^{2-}).

📐Formulae

A=Z+N (where N is the number of neutrons)A = Z + N \text{ (where } N \text{ is the number of neutrons)}

Ar=(isotopic mass×percentage abundance)100A_r = \frac{\sum (\text{isotopic mass} \times \text{percentage abundance})}{100}

Number of electrons in neutral atom=Atomic Number (Z)\text{Number of electrons in neutral atom} = \text{Atomic Number (Z)}

Charge of an Ion=ProtonsElectrons\text{Charge of an Ion} = \text{Protons} - \text{Electrons}

💡Examples

Problem 1:

Calculate the Relative Atomic Mass (ArA_r) of Chlorine, given that it consists of 75%75\% of 35Cl^{35}Cl and 25%25\% of 37Cl^{37}Cl.

Solution:

Ar=(35×75)+(37×25)100=35.5A_r = \frac{(35 \times 75) + (37 \times 25)}{100} = 35.5

Explanation:

The ArA_r is the weighted average of the isotopic masses based on their natural abundance.

Problem 2:

Determine the number of protons, neutrons, and electrons in an Aluminum ion, 1327Al3+^{27}_{13}Al^{3+}.

Solution:

Protons = 1313, Neutrons = 1414, Electrons = 1010.

Explanation:

The atomic number 1313 indicates 1313 protons. Neutrons are calculated as AZ=2713=14A - Z = 27 - 13 = 14. A 3+3+ charge means the atom lost 33 electrons, so 133=1013 - 3 = 10.

Problem 3:

Write the electronic configuration for a Phosphorus atom (Z=15Z = 15) and state its Group number in the Periodic Table.

Solution:

Configuration: 2,8,52, 8, 5. Group number: VV (or 1515).

Explanation:

Phosphorus has 1515 electrons. The first shell takes 22, the second 88, leaving 55 for the valence shell. The number of valence electrons (55) determines the Group number.