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Chemistry - Metallurgy

Grade 10ICSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Minerals and Ores: Minerals are naturally occurring compounds of metals found in the earth's crust. Ores are those minerals from which metals can be extracted profitably and easily. For example, Bauxite (Al2O3β‹…2H2OAl_2O_3 \cdot 2H_2O) is the primary ore of Aluminium.

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Common Ores: Aluminium (Bauxite - Al2O3β‹…2H2OAl_2O_3 \cdot 2H_2O), Iron (Haematite - Fe2O3Fe_2O_3), Zinc (Zinc Blende - ZnSZnS; Calamine - ZnCO3ZnCO_3).

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Concentration of Ore (Benificiation): The process of removing gangue (earthy impurities) from the ore. Methods include Magnetic Separation, Froth Floatation (for sulphide ores like ZnSZnS), and Leaching (chemical separation like Baeyer's Process for Al2O3Al_2O_3).

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Calcination vs. Roasting: Calcination is heating the ore in the absence or limited supply of air to decompose carbonates (ZnCO3β†’Ξ”ZnO+CO2ZnCO_3 \xrightarrow{\Delta} ZnO + CO_2). Roasting is heating the ore in excess air to convert sulphides to oxides (2ZnS+3O2β†’Ξ”2ZnO+2SO22ZnS + 3O_2 \xrightarrow{\Delta} 2ZnO + 2SO_2).

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Reduction: The process of converting metal oxides to free metals. Active metals like AlAl are extracted by Electrolytic Reduction, while moderately active metals like ZnZn and FeFe are reduced using Carbon/Coke (ZnO+C→Zn+COZnO + C \rightarrow Zn + CO).

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Hall-HΓ©roult Process: The electrolytic reduction of fused Alumina. The electrolyte consists of a mixture of Alumina (Al2O3Al_2O_3), Cryolite (Na3AlF6Na_3AlF_6), and Fluorspar (CaF2CaF_2).

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Alloys: Homogeneous mixtures of two or more metals or a metal and a non-metal. Examples: Brass (Cu+ZnCu + Zn), Bronze (Cu+SnCu + Sn), and Stainless Steel (Fe+Cr+Ni+CFe + Cr + Ni + C).

πŸ“Formulae

Al2O3⋅2H2O+2NaOH→2NaAlO2+3H2OAl_2O_3 \cdot 2H_2O + 2NaOH \rightarrow 2NaAlO_2 + 3H_2O

NaAlO2+2H2Oβ†’Al(OH)3↓+NaOHNaAlO_2 + 2H_2O \rightarrow Al(OH)_3 \downarrow + NaOH

2Al(OH)3β†’1100∘CAl2O3+3H2O2Al(OH)_3 \xrightarrow{1100^{\circ}C} Al_2O_3 + 3H_2O

AtΒ CathodeΒ (Reduction):Β Al3++3eβˆ’β†’Al\text{At Cathode (Reduction): } Al^{3+} + 3e^- \rightarrow Al

AtΒ AnodeΒ (Oxidation):Β 2O2βˆ’βˆ’4eβˆ’β†’O2\text{At Anode (Oxidation): } 2O^{2-} - 4e^- \rightarrow O_2

2ZnO+C→2Zn+CO22ZnO + C \rightarrow 2Zn + CO_2

Fe2O3+3CO→2Fe+3CO2Fe_2O_3 + 3CO \rightarrow 2Fe + 3CO_2

πŸ’‘Examples

Problem 1:

Explain the role of Cryolite (Na3AlF6Na_3AlF_6) and Fluorspar (CaF2CaF_2) in the electrolytic reduction of Alumina.

Solution:

  1. Lowering Melting Point: Pure Alumina melts at approx 2050∘C2050^{\circ}C. The addition of Cryolite and Fluorspar brings it down to about 950∘C950^{\circ}C.
  2. Increasing Conductivity: Alumina is a poor conductor of electricity; Cryolite provides ions to enhance conductivity.

Explanation:

In the Hall-HΓ©roult process, using pure Al2O3Al_2O_3 is energy-intensive and causes the metal to vaporize. The additives make the process economically viable and safer.

Problem 2:

Identify the process and give the chemical equation for converting Zinc Blende (ZnSZnS) into Zinc Oxide.

Solution:

Process: Roasting. Equation: 2ZnS+3O2β†’Ξ”2ZnO+2SO22ZnS + 3O_2 \xrightarrow{\Delta} 2ZnO + 2SO_2

Explanation:

Sulphide ores are converted to oxides by heating them strongly in the presence of excess oxygen (Roasting) so that they can be easily reduced by Carbon later.

Problem 3:

Why are the graphite anodes in the Hall-HΓ©roult process replaced periodically?

Solution:

The oxygen evolved at the anode reacts with the graphite (carbon) to form carbon dioxide: C+O2β†’CO2C + O_2 \rightarrow CO_2

Explanation:

Because the carbon rods are oxidized and consumed by the oxygen produced during electrolysis, they gradually wear away and must be replaced.

Metallurgy - Revision Notes & Key Formulas | ICSE Class 10 Science