krit.club logo

Physics - Atomic and Nuclear Physics (Radioactivity and Half-life)

Grade 10IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Atomic Structure: An atom consists of a nucleus containing protons and neutrons, surrounded by electrons. It is represented as ZAX^{A}_{Z}X, where AA is the nucleon (mass) number and ZZ is the proton (atomic) number.

Isotopes: Atoms of the same element with the same number of protons (ZZ) but different numbers of neutrons, resulting in a different mass number (AA).

Radioactive Decay: A random and spontaneous process where unstable nuclei emit radiation to become more stable. The three main types are Alpha (α\alpha), Beta (β\beta), and Gamma (γ\gamma).

Alpha Decay: Emission of a helium nucleus 24He^{4}_{2}He. The parent nucleus loses 2 protons and 2 neutrons, decreasing AA by 4 and ZZ by 2.

Beta Decay (β\beta^-): A neutron decays into a proton and an electron (10e^{0}_{-1}e). AA remains the same, but ZZ increases by 1.

Gamma Radiation: High-energy electromagnetic waves with no mass or charge. It often follows α\alpha or β\beta decay to release excess energy.

Half-life (T1/2T_{1/2}): The time taken for half the radioactive nuclei in a sample to decay, or for the activity (measured in Becquerels, BqBq) to fall to half its initial value.

Background Radiation: Low-level ionizing radiation that is constantly present in the environment from natural sources (radon gas, cosmic rays) and artificial sources (medical X-rays, nuclear fallout).

📐Formulae

ZAXZ2A4Y+24He+energy^{A}_{Z}X \rightarrow ^{A-4}_{Z-2}Y + ^{4}_{2}He + \text{energy}

ZAXZ+1AY+10e+νˉ+energy^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + ^{0}_{-1}e + \bar{\nu} + \text{energy}

N=N0(12)nN = N_0 \left(\frac{1}{2}\right)^n

n=tT1/2n = \frac{t}{T_{1/2}}

A=A0(12)tT1/2A = A_0 \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}}

💡Examples

Problem 1:

A radioactive sample of Iodine-131 has an initial activity of 1600 Bq1600\ Bq. If the half-life of Iodine-131 is 88 days, calculate the activity remaining after 2424 days.

Solution:

  1. Determine the number of half-lives (nn): n=Total timeHalf-life=24 days8 days=3n = \frac{\text{Total time}}{\text{Half-life}} = \frac{24\text{ days}}{8\text{ days}} = 3.
  2. Apply the decay formula: A=A0×(12)n=1600×(12)3A = A_0 \times (\frac{1}{2})^n = 1600 \times (\frac{1}{2})^3.
  3. Calculate the result: A=1600×18=200 BqA = 1600 \times \frac{1}{8} = 200\ Bq.

Explanation:

After 3 half-lives, the activity halves three times: 1600800400200 Bq1600 \rightarrow 800 \rightarrow 400 \rightarrow 200\ Bq.

Problem 2:

Complete the following nuclear equation for the alpha decay of Radium-226: 88226RaZARn+24He^{226}_{88}Ra \rightarrow ^{A}_{Z}Rn + ^{4}_{2}He. Find AA and ZZ.

Solution:

Using the conservation of mass and atomic numbers: 226=A+4A=222226 = A + 4 \Rightarrow A = 222 88=Z+2Z=8688 = Z + 2 \Rightarrow Z = 86 The resulting nucleus is 86222Rn^{222}_{86}Rn.

Explanation:

In Alpha decay, the total mass number and atomic number must be equal on both sides of the equation.