Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Radioactivity is the spontaneous and random emission of radiation from the unstable nucleus of an atom. It is unaffected by chemical or physical conditions such as temperature or pressure.
The structure of the nucleus is represented by the notation , where is the nucleon (mass) number and is the proton (atomic) number.
Alpha () decay: The emission of a helium nucleus . The mass number decreases by and the atomic number decreases by . Equation: .
Beta-minus () decay: A neutron in the nucleus decays into a proton and an electron. The electron and an antineutrino are emitted. The atomic number increases by . Equation: .
Gamma () radiation: High-energy electromagnetic waves emitted to allow the nucleus to reach a lower energy state. There is no change to or .
Activity () is the rate at which a source decays, measured in Becquerels ().
Half-life () is the average time taken for half of the radioactive nuclei in a sample to decay, or for the activity to fall to half of its initial value.
Nuclear Fission: The splitting of a heavy nucleus (e.g., ) into two smaller daughter nuclei and neutrons, releasing a large amount of energy.
Nuclear Fusion: The process where two light nuclei (e.g., isotopes of Hydrogen like and ) combine to form a heavier nucleus, releasing energy.
📐Formulae
💡Examples
Problem 1:
A sample of radioactive material has an initial activity of . If the half-life of the isotope is hours, calculate the activity of the sample after hours.
Solution:
Step 1: Calculate the number of half-lives (): . Step 2: Use the activity formula: .
Explanation:
Since hours represents exactly three half-life periods, the activity halves three times ().
Problem 2:
Complete the nuclear equation for the alpha decay of Radium-226: .
Solution:
According to the conservation of nucleon number: . According to the conservation of proton number: . The resulting nucleus is Radon: .
Explanation:
In decay, the parent nucleus loses two protons and two neutrons, reducing the mass number by and the atomic number by .