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Magnetic Effects of Current and Magnetism - Magnetic Properties of Materials (Dia, Para, Ferro)

Grade 12ICSEPhysics

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Magnetization (MM): It is the net magnetic moment per unit volume of the material, expressed as M=mnetVM = \frac{m_{net}}{V}. Its SI unit is A/mA/m.

Magnetic Intensity (HH): The external magnetic field that induces magnetism in a material. The relation between BB, HH, and MM is given by B=μ0(H+M)B = \mu_0(H + M).

Magnetic Susceptibility (χ\chi): It measures how easily a substance can be magnetized. It is defined as the ratio of the intensity of magnetization to the magnetic intensity: χ=MH\chi = \frac{M}{H}.

Relative Permeability (μr\mu_r): The ratio of the permeability of the medium to the permeability of free space. It is related to susceptibility by the equation μr=1+χ\mu_r = 1 + \chi.

Diamagnetic Materials: These are substances that develop weak magnetization in a direction opposite to the external magnetic field. Their susceptibility χ\chi is small and negative (e.g., BiBi, CuCu, H2OH_2O).

Paramagnetic Materials: These substances develop weak magnetization in the same direction as the external field. Their susceptibility χ\chi is small and positive (e.g., AlAl, NaNa, O2O_2).

Ferromagnetic Materials: These substances develop strong magnetization in the direction of the external field. They exhibit domain structure and have very large positive susceptibility χ\chi (e.g., FeFe, CoCo, NiNi).

Curie's Law: For paramagnetic materials, the magnetic susceptibility is inversely proportional to the absolute temperature TT, expressed as χ=CT\chi = \frac{C}{T}, where CC is the Curie constant.

Curie Temperature (TCT_C): The temperature above which a ferromagnetic material transitions into a paramagnetic material. The susceptibility follows the Curie-Weiss Law: χ=CTTC\chi = \frac{C}{T - T_C} for T>TCT > T_C.

Hysteresis: The phenomenon where the magnetic induction BB lags behind the magnetizing field HH. Key points include Retentivity (residual BB when H=0H=0) and Coercivity (reverse HH needed to make B=0B=0).

📐Formulae

M=mnetVM = \frac{m_{net}}{V}

B=μ0(H+M)B = \mu_0(H + M)

χ=MH\chi = \frac{M}{H}

μr=1+χ\mu_r = 1 + \chi

μ=μ0μr\mu = \mu_0 \mu_r

χ=CT\chi = \frac{C}{T}

χ=CTTC (for T>TC)\chi = \frac{C}{T - T_C} \text{ (for } T > T_C \text{)}

💡Examples

Problem 1:

A magnetic material has a relative permeability μr=5001\mu_r = 5001. Identify the type of magnetic material and calculate its magnetic susceptibility χ\chi.

Solution:

Using the relation μr=1+χ\mu_r = 1 + \chi, we get χ=μr1\chi = \mu_r - 1. Substituting the value: χ=50011=5000\chi = 5001 - 1 = 5000.

Explanation:

Since the susceptibility χ\chi is very large and positive (50005000), the material is classified as a ferromagnetic material.

Problem 2:

The susceptibility of a paramagnetic magnesium sample is 1.2×1051.2 \times 10^{-5} at 300K300 \, K. What will be its susceptibility at 600K600 \, K?

Solution:

According to Curie's Law, χ1T\chi \propto \frac{1}{T}. Therefore, χ1χ2=T2T1\frac{\chi_1}{\chi_2} = \frac{T_2}{T_1}. Substituting the values: 1.2×105χ2=600300=2\frac{1.2 \times 10^{-5}}{\chi_2} = \frac{600}{300} = 2. Thus, χ2=1.2×1052=0.6×105\chi_2 = \frac{1.2 \times 10^{-5}}{2} = 0.6 \times 10^{-5}.

Explanation:

As the temperature increases, the thermal agitation increases, making it harder for the dipoles to align with the field, thus reducing the susceptibility.

Magnetic Properties of Materials (Dia, Para, Ferro) Revision - Class 12 Physics ICSE