Dual Nature of Radiation and Matter

The number of photons emitted per second by a light source of power $P$ and frequency $\\nu$ is:

Which of the following is the correct Einstein's photoelectric equation?

If the energy of a photon is $3.3 \\times 10^{-19} \\text{ J}$, its approximate energy in electron-volts is:

Photoelectric emission occurs only when the incident light has more than a certain minimum:

If the distance between the point source of light and the photocathode is tripled, the saturation current becomes:

A photon of wavelength $3310\text{ \AA}$ is incident on a metal. If $h = 6.62 \times 10^{-34}\text{ J s}$, the energy of the photon is:

The energy of a photon of wavelength $\lambda$ is $E$. What is the energy of a photon of wavelength $\lambda/2$?

In a photoelectric experiment, the stopping potential $V_s$ was measured for various frequencies $\nu$ of the incident light. The data was used to calculate Planck's constant $h$. If the charge of the electron used in the calculation was slightly larger than its actual value, the calculated value of $h$ would be:

Light of frequency $1.5\nu_0$ is incident on a photosensitive material of threshold frequency $\nu_0$. If the frequency is halved and intensity is doubled, the photoelectric current becomes:

The maximum kinetic energy of photoelectrons is $K_{max}$. If the frequency of incident light is increased by $20\%$, the new maximum kinetic energy becomes $K'_{max}$. Which of the following is correct?

What is the value of the slope of the graph of photoelectric current versus intensity of incident radiation?

If light of wavelength $\lambda$ falls on a metal of work function $\phi_0$, the condition for no emission of photoelectrons is:

Which observation about the photoelectric effect contradicted the wave theory of light?

If the frequency of light is doubled, what happens to the energy of each photon?

Calculate the energy of a photon (in eV) having a wavelength of $4000 \text{ \AA}$. ($h = 6.63 \times 10^{-34} \text{ J}\cdot\text{s}, c = 3 \times 10^8 \text{ m/s}$)

If we plot a graph of stopping potential $V_0$ against $1/\lambda$, the intercept on the $1/\lambda$ axis represents:

What happens to the slope of the $V_0$ vs $\nu$ graph if we change the metal of the cathode?

An electron and a proton have the same kinetic energy. The ratio of their de Broglie wavelengths ($\lambda_e / \lambda_p$) is approximately:

The maximum velocity of a photoelectron is $2 \times 10^6 \text{ m/s}$. If the specific charge of an electron is $1.76 \times 10^{11} \text{ C/kg}$, the stopping potential is approximately:

The work function of a metal is $h\nu_0$. If light of frequency $4\nu_0$ is incident on the metal, the maximum kinetic energy of the photoelectrons is:

If the energy of a photon is $E$, then its momentum is:

The de Broglie wavelength of an electron moving with a speed of $10^7$ m/s is of the order of:

Planck's constant has the dimensions of:

Which of the following is true for the de Broglie wavelength of a particle?

Two particles $A$ and $B$ with the same charge are accelerated from rest through the same potential difference $V$. If the ratio of their De Broglie wavelengths is $\lambda_A : \lambda_B = 1 : 2$, determine the ratio of their masses $m_A : m_B$.

Which of the following is the correct unit for the product of momentum and De Broglie wavelength?

A particle $A$ has twice the momentum of particle $B$. The ratio of their De Broglie wavelengths ($\\lambda_A : \\lambda_B$) is:

If the de Broglie wavelength of a particle of mass $m$ is equal to the radius of its circular path in a magnetic field $B$, then the charge $q$ of the particle is:

A photon and an electron both have a wavelength of $1\,nm$. The ratio of the energy of the photon to the total relativistic energy of the electron is (where $m_0$ is electron rest mass):

The de Broglie wavelength of an electron in a certain state is $10^{-10}\,m$. If the electron's velocity is halved, the new de Broglie wavelength will be: