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Magnetism and Matter - Para-, Dia-, and Ferro-magnetic substances

Grade 12CBSEPhysics

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Magnetic Intensity (HH) and Magnetization (MM): Magnetic intensity HH is the external magnetic field applied, while Intensity of Magnetization MM is the magnetic moment per unit volume developed inside the material, expressed as M=mnetVM = \frac{m_{net}}{V}.

Magnetic Susceptibility (χ\chi): It is the ratio of the intensity of magnetization MM to the magnetic intensity HH. Mathematically, χ=MH\chi = \frac{M}{H}.

Diamagnetic Substances: These substances develop weak magnetization in a direction opposite to the external magnetic field. They have a small, negative susceptibility (χ<0\chi < 0) and relative permeability μr<1\mu_r < 1. Examples include BiBi, CuCu, and H2OH_2O.

Paramagnetic Substances: These substances develop weak magnetization in the same direction as the external field. They have a small, positive susceptibility (χ>0\chi > 0) and μr>1\mu_r > 1. Examples include AlAl, NaNa, and O2O_2 at STP.

Ferromagnetic Substances: These substances develop strong magnetization in the direction of the field due to the alignment of 'domains'. They have very large, positive susceptibility (χ1\chi \gg 1) and μr1\mu_r \gg 1. Examples include FeFe, CoCo, and NiNi.

Curie's Law: For paramagnetic materials, the magnetic susceptibility is inversely proportional to the absolute temperature TT. Thus, χ=CT\chi = \frac{C}{T}, where CC is the Curie constant.

Curie Temperature (TcT_c): The temperature above which a ferromagnetic substance loses its ferromagnetic properties and becomes paramagnetic. The susceptibility for T>TcT > T_c follows the Curie-Weiss law: χ=CTTc\chi = \frac{C}{T - T_c}.

Meissner Effect: A superconductor is a perfect diamagnet with χ=1\chi = -1 and μr=0\mu_r = 0. It expels all magnetic flux from its interior.

📐Formulae

μr=1+χ\mu_r = 1 + \chi

B=μ0(H+M)B = \mu_0 (H + M)

M=χHM = \chi H

χ=CT (Curie’s Law for Paramagnets)\chi = \frac{C}{T} \text{ (Curie's Law for Paramagnets)}

χ=CTTc (Curie-Weiss Law for Ferromagnets, T>Tc)\chi = \frac{C}{T - T_c} \text{ (Curie-Weiss Law for Ferromagnets, } T > T_c)

B=μH=μ0μrHB = \mu H = \mu_0 \mu_r H

💡Examples

Problem 1:

A paramagnetic sample shows a net magnetization of 8 Am18 \text{ Am}^{-1} when placed in an external magnetic field of 0.6 T0.6 \text{ T} at a temperature of 4 K4 \text{ K}. When the same sample is placed in an external magnetic field of 0.2 T0.2 \text{ T} at a temperature of 16 K16 \text{ K}, what will be the magnetization?

Solution:

According to Curie's Law, MBTM \propto \frac{B}{T}. Therefore, M2M1=B2B1×T1T2\frac{M_2}{M_1} = \frac{B_2}{B_1} \times \frac{T_1}{T_2}. Given M1=8 Am1M_1 = 8 \text{ Am}^{-1}, B1=0.6 TB_1 = 0.6 \text{ T}, T1=4 KT_1 = 4 \text{ K}, B2=0.2 TB_2 = 0.2 \text{ T}, and T2=16 KT_2 = 16 \text{ K}. Substituting the values: M28=0.20.6×416=13×14=112\frac{M_2}{8} = \frac{0.2}{0.6} \times \frac{4}{16} = \frac{1}{3} \times \frac{1}{4} = \frac{1}{12}. Thus, M2=812=230.67 Am1M_2 = \frac{8}{12} = \frac{2}{3} \approx 0.67 \text{ Am}^{-1}.

Explanation:

This problem applies Curie's Law, which states that for a paramagnetic material, magnetization is directly proportional to the magnetic field and inversely proportional to the absolute temperature.

Problem 2:

The magnetic susceptibility of a material is 0.00002-0.00002. Identify the type of magnetic material and calculate its relative permeability μr\mu_r.

Solution:

Since the susceptibility χ=0.00002\chi = -0.00002 is negative and small, the material is diamagnetic. The relative permeability is calculated as μr=1+χ\mu_r = 1 + \chi. Therefore, μr=1+(0.00002)=0.99998\mu_r = 1 + (-0.00002) = 0.99998.

Explanation:

Diamagnetic substances are characterized by a negative susceptibility because their induced magnetic moment opposes the external field. The relation μr=1+χ\mu_r = 1 + \chi shows that μr\mu_r for such materials is slightly less than 1.

Para-, Dia-, and Ferro-magnetic substances Revision - Class 12 Physics CBSE