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Nuclear Physics - The nuclear model of the atom

Grade 11IGCSEPhysics

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Rutherford alpha-particle scattering experiment: Most α\alpha-particles passed through gold foil undeflected, showing the atom is mostly empty space. A small number were deflected at large angles, proving the existence of a tiny, dense, positively charged nucleus.

Atomic structure: The atom consists of a central nucleus containing protons and neutrons, surrounded by electrons orbiting in shells.

Protons: Relative mass of 11, relative charge of +1+1. The number of protons is the atomic (proton) number ZZ.

Neutrons: Relative mass of 11, relative charge of 00. These are found in the nucleus and provide stability.

Electrons: Relative mass of 11836\frac{1}{1836} (negligible), relative charge of 1-1. In a neutral atom, the number of electrons equals the number of protons.

Nuclide notation: Represented as ZAX^{A}_{Z}X, where AA is the nucleon (mass) number and ZZ is the proton (atomic) number.

Isotopes: Atoms of the same element with the same number of protons (ZZ) but different numbers of neutrons (different AA). They share identical chemical properties due to having the same electron configuration.

📐Formulae

A=Z+NA = Z + N

N=AZN = A - Z

Net Charge=(number of protonsnumber of electrons)×e\text{Net Charge} = (\text{number of protons} - \text{number of electrons}) \times e

💡Examples

Problem 1:

A neutral atom of Sodium is represented by the nuclide notation 1123Na^{23}_{11}\text{Na}. Determine the number of protons, neutrons, and electrons present.

Solution:

Protons = 1111, Neutrons = 1212, Electrons = 1111.

Explanation:

The atomic number ZZ is the lower number, so there are 1111 protons. Since the atom is neutral, there are also 1111 electrons. The nucleon number AA is 2323, so the number of neutrons NN is calculated using AZ=2311=12A - Z = 23 - 11 = 12.

Problem 2:

Chlorine has two common isotopes: 1735Cl^{35}_{17}\text{Cl} and 1737Cl^{37}_{17}\text{Cl}. State the difference in their nuclear composition.

Solution:

1737Cl^{37}_{17}\text{Cl} has 22 more neutrons than 1735Cl^{35}_{17}\text{Cl}.

Explanation:

Both isotopes have 1717 protons (same element). For 1735Cl^{35}_{17}\text{Cl}, N=3517=18N = 35 - 17 = 18 neutrons. For 1737Cl^{37}_{17}\text{Cl}, N=3717=20N = 37 - 17 = 20 neutrons.

The nuclear model of the atom - Revision Notes & Key Formulas | IGCSE Grade 11 Physics