krit.club logo

Motion, Forces and Energy - Mass, weight and density

Grade 11A LevelPhysics

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

Mass (mm) is a measure of the quantity of matter in an object at rest relative to the observer. It is measured in kilograms (kgkg) and remains constant regardless of location.

•

Weight (WW) is the gravitational force acting on an object that has mass. It is measured in Newtons (NN) and changes depending on the gravitational field strength (gg).

•

The gravitational field strength (gg) is the force per unit mass, expressed as g=Wmg = \frac{W}{m}. On Earth, gg is approximately 9.8 N/kg9.8 \text{ N/kg} (or 10 N/kg10 \text{ N/kg} for some IGCSE syllabus variations).

•

Density (ρ\rho) is defined as the mass per unit volume of a substance. The standard SI unit is kg/m3kg/m^3, but g/cm3g/cm^3 is frequently used in laboratory experiments (1 g/cm3=1000 kg/m31 \text{ g/cm}^3 = 1000 \text{ kg/m}^3).

•

To determine the density of an irregularly shaped solid, the displacement method is used: the volume of the solid is equal to the volume of liquid it displaces in a measuring cylinder.

•

Objects float in a fluid if their density is less than the density of the fluid (ρobject<ρfluid\rho_{object} < \rho_{fluid}) and sink if their density is greater.

📐Formulae

W=m⋅gW = m \cdot g

ρ=mV\rho = \frac{m}{V}

Virregular=Vfinal−VinitialV_{irregular} = V_{final} - V_{initial}

💡Examples

Problem 1:

A piece of rock has a mass of 450 g450 \text{ g} and a volume of 150 cm3150 \text{ cm}^3. Calculate its density in kg/m3kg/m^3.

Solution:

First, calculate density in g/cm3g/cm^3: ρ=450 g150 cm3=3 g/cm3\rho = \frac{450 \text{ g}}{150 \text{ cm}^3} = 3 \text{ g/cm}^3. Convert to kg/m3kg/m^3: 3×1000=3000 kg/m33 \times 1000 = 3000 \text{ kg/m}^3.

Explanation:

Density is found by dividing mass by volume. To convert from g/cm3g/cm^3 to kg/m3kg/m^3, we multiply by 10001000 because there are 1000 g1000 \text{ g} in a kgkg and 1,000,000 cm31,000,000 \text{ cm}^3 in a m3m^3.

Problem 2:

An object weighs 200 N200 \text{ N} on Earth (g=10 N/kgg = 10 \text{ N/kg}). What is its mass, and how much would it weigh on Mars where g=3.7 N/kgg = 3.7 \text{ N/kg}?

Solution:

Mass on Earth: m=Wg=200 N10 N/kg=20 kgm = \frac{W}{g} = \frac{200 \text{ N}}{10 \text{ N/kg}} = 20 \text{ kg}. Weight on Mars: W=m⋅gmars=20 kg×3.7 N/kg=74 NW = m \cdot g_{mars} = 20 \text{ kg} \times 3.7 \text{ N/kg} = 74 \text{ N}.

Explanation:

The mass of the object is constant (20 kg20 \text{ kg}) across the universe. The weight changes because the gravitational field strength gg is different on Mars compared to Earth.