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Organic Chemistry - Alkenes

Grade 12IGCSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Alkenes are unsaturated hydrocarbons containing at least one carbon-to-carbon double bond (C=CC=C).

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The general molecular formula for alkenes is CnH2nC_nH_{2n}.

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The C=CC=C double bond consists of one Οƒ\sigma (sigma) bond and one Ο€\pi (pi) bond. The Ο€\pi bond is an area of high electron density, making alkenes more reactive than alkanes.

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Alkenes undergo addition reactions, where the Ο€\pi bond breaks and atoms are added to the carbon atoms previously involved in the double bond.

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Bromine water test: When an alkene is added to orange-brown bromine water (Br2(aq)Br_2(aq)), the solution becomes colorless. This is a standard test for unsaturation.

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Hydrogenation involves the addition of H2H_2 to an alkene in the presence of a Nickel (NiNi) catalyst at approximately 150∘C150^\circ C to form an alkane.

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Hydration is the reaction of an alkene with steam (H2O(g)H_2O(g)) in the presence of a phosphoric acid (H3PO4H_3PO_4) catalyst at 300∘C300^\circ C and 60 atm60\text{ atm} pressure to produce an alcohol.

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Addition polymerization occurs when many small alkene molecules (monomers) join together to form a long-chain molecule (polymer) by breaking their double bonds.

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Stereoisomerism (E/ZE/Z or cis/transcis/trans) occurs in alkenes because the double bond restricts rotation, leading to different spatial arrangements of substituent groups.

πŸ“Formulae

CnH2nC_nH_{2n}

C2H4+Br2β†’CH2BrCH2BrC_2H_4 + Br_2 \rightarrow CH_2BrCH_2Br

CnH2n+H2β†’Ni,150∘CCnH2n+2C_nH_{2n} + H_2 \xrightarrow{Ni, 150^\circ C} C_nH_{2n+2}

C2H4(g)+H2O(g)β†’H3PO4,300∘C,60Β atmC2H5OH(g)C_2H_4(g) + H_2O(g) \xrightarrow{H_3PO_4, 300^\circ C, 60\text{ atm}} C_2H_5OH(g)

n(CH2=CH2)β†’β€”[CH2βˆ’CH2]nβ€”n(CH_2=CH_2) \rightarrow \text{---}[CH_2-CH_2]_n\text{---}

πŸ’‘Examples

Problem 1:

Predict the product formed when Propene (C3H6C_3H_6) reacts with Hydrogen Chloride (HClHCl) and state the name of the reaction.

Solution:

C3H6+HCl→C3H7ClC_3H_6 + HCl \rightarrow C_3H_7Cl. The major product is 2-chloropropane (CH3CHClCH3CH_3CHClCH_3).

Explanation:

This is an electrophilic addition reaction. According to Markovnikov's rule, the hydrogen atom from HClHCl attaches to the carbon atom of the double bond that already has the greater number of hydrogen atoms, resulting in 2-chloropropane as the major product.

Problem 2:

Write the balanced chemical equation for the complete combustion of Butene (C4H8C_4H_8).

Solution:

C4H8+6O2β†’4CO2+4H2OC_4H_8 + 6O_2 \rightarrow 4CO_2 + 4H_2O

Explanation:

In complete combustion, the hydrocarbon reacts with excess oxygen (O2O_2) to produce carbon dioxide (CO2CO_2) and water (H2OH_2O). The equation must be balanced to ensure the number of atoms of each element is the same on both sides.

Problem 3:

An alkene has a molar mass of 56Β g/mol56\text{ g/mol}. Determine its molecular formula.

Solution:

C4H8C_4H_8

Explanation:

Using the general formula CnH2nC_nH_{2n}, the molar mass is calculated as n(12.0)+2n(1.0)=56n(12.0) + 2n(1.0) = 56. Solving for nn: 14n=56β‡’n=414n = 56 \Rightarrow n = 4. Therefore, the formula is C4H8C_4H_8 (Butene).

Alkenes - Revision Notes & Key Formulas | IGCSE Grade 12 Chemistry