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Atoms, Elements and Compounds - Ionic bonding

Grade 12IGCSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Ionic bonding is the strong electrostatic attraction between oppositely charged ions (cationscations and anionsanions).

It typically occurs between metals and non-metals through the transfer of valence electrons to achieve a stable noble gas electronic configuration (the octet rule).

Metals undergo oxidation to form positive ions: MMn++neM \rightarrow M^{n+} + ne^-. For example, NaNa++eNa \rightarrow Na^+ + e^-.

Non-metals undergo reduction to form negative ions: X+neXnX + ne^- \rightarrow X^{n-}. For example, Cl+eClCl + e^- \rightarrow Cl^-.

Ionic compounds form a giant ionic lattice, a regular 3D3D arrangement where every positive ion is surrounded by negative ions and vice versa.

Physical properties include high melting and boiling points due to the large amount of energy needed to break the strong electrostatic forces in the lattice.

Ionic compounds are brittle because a blow can shift the layers of ions, causing ions of the same charge to align and repel each other.

They conduct electricity only when molten or in aqueous solution (electrolyteselectrolytes) because the ions are free to move; in solid state, ions are fixed in the lattice.

📐Formulae

F=kq1q2r2F = k \frac{q_1 q_2}{r^2} (Coulombic force of attraction between ions)

M(s)Mn+(g)+neM(s) \rightarrow M^{n+}(g) + ne^- (Ionization energy process)

Net Charge=(positive charges)+(negative charges)=0\text{Net Charge} = \sum (\text{positive charges}) + \sum (\text{negative charges}) = 0

Uz+zr++rU \propto \frac{z_+ z_-}{r_+ + r_-} (Lattice energy relationship)

💡Examples

Problem 1:

Explain the formation of Magnesium Chloride and provide its chemical formula.

Solution:

Magnesium (MgMg) is in Group 2 and has the configuration [Ne]3s2[Ne] 3s^2. It loses 22 electrons to form Mg2+Mg^{2+}. Chlorine (ClCl) is in Group 17 and has the configuration [Ne]3s23p5[Ne] 3s^2 3p^5. Each ClCl atom gains 11 electron to form ClCl^-. To balance the charges, one Mg2+Mg^{2+} ion reacts with two ClCl^- ions, resulting in MgCl2MgCl_2.

Explanation:

The total positive charge (+2+2) must equal the total negative charge (2×1=22 \times -1 = -2) to ensure the compound is electrically neutral.

Problem 2:

Predict whether MgOMgO or NaClNaCl has a higher melting point and justify your answer.

Solution:

MgOMgO has a significantly higher melting point than NaClNaCl.

Explanation:

Melting point depends on the strength of the ionic bond (lattice energy). In MgOMgO, the ions are Mg2+Mg^{2+} and O2O^{2-}, while in NaClNaCl they are Na+Na^+ and ClCl^-. Since the product of the charges in MgOMgO (2×2=42 \times 2 = 4) is greater than in NaClNaCl (1×1=11 \times 1 = 1), and the ionic radii are smaller, the electrostatic attraction is much stronger in MgOMgO.

Ionic bonding - Revision Notes & Key Formulas | IGCSE Grade 12 Chemistry