Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
An Ideal Solution is a solution that obeys Raoult's Law at all concentrations and temperatures. For such solutions, the enthalpy of mixing and the volume of mixing .
In an Ideal Solution, the intermolecular attractive forces between the solute and solvent ( interactions) are nearly equal to those between the solute-solute () and solvent-solvent () molecules.
Non-ideal solutions deviate from Raoult's Law. These are classified into solutions showing positive deviation and negative deviation.
Positive Deviation occurs when interactions are weaker than and interactions. This leads to (endothermic) and . The vapor pressure of the solution is higher than predicted by Raoult's Law.
Negative Deviation occurs when interactions are stronger than and interactions. This leads to (exothermic) and . The vapor pressure of the solution is lower than predicted by Raoult's Law.
Azeotropes are binary mixtures having the same composition in liquid and vapor phase and boil at a constant temperature. Minimum boiling azeotropes are formed by solutions showing large positive deviation (e.g., Ethanol solution), while Maximum boiling azeotropes are formed by solutions showing large negative deviation (e.g., ).
📐Formulae
💡Examples
Problem 1:
Vapor pressure of pure benzene () and toluene () at are and respectively. Calculate the total vapor pressure of an ideal solution containing of benzene and of toluene.
Solution:
- Moles of Benzene () = .
- Moles of Toluene () = .
- Mole fraction of Benzene () = .
- Mole fraction of Toluene () = .
- .
Explanation:
Since the solution is ideal, we apply Raoult's Law directly using the mole fractions and pure component vapor pressures.
Problem 2:
Predict the type of deviation shown by a mixture of Chloroform () and Acetone ().
Solution:
Negative Deviation.
Explanation:
Chloroform and Acetone molecules form intermolecular hydrogen bonds (). This interaction is stronger than the original and interactions, leading to a decrease in vapor pressure.
Problem 3:
A mixture of Ethanol () and Acetone () shows positive deviation. Why?
Solution:
In pure ethanol, molecules are hydrogen-bonded. On adding acetone, its molecules get in between the ethanol molecules and break some of the hydrogen bonds. This weakens the intermolecular attractions (), increasing the tendency of molecules to escape into the vapor phase.
Explanation:
Weakening of intermolecular forces leads to higher vapor pressure than predicted, characteristic of positive deviation.