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Haloalkanes and Haloarenes - Reactions of haloarenes

Grade 12ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Haloarenes are significantly less reactive towards Nucleophilic Substitution (SNS_N) reactions compared to haloalkanes due to resonance effects, difference in hybridization of the carbon atom in the CXC-X bond (sp2sp^2 vs sp3sp^3), and instability of the phenyl cation.

Resonance Effect: The electron pairs on the halogen atom are in conjugation with π\pi electrons of the ring, resulting in a partial double bond character in the CXC-X bond, making it difficult to break.

Nucleophilic substitution can occur under drastic conditions (high temperature and pressure), such as in the Dow's Process for the synthesis of Phenol.

Presence of electron-withdrawing groups (EWG) like NO2-NO_2 at ortho and para positions increases the reactivity of haloarenes towards nucleophilic substitution.

Electrophilic Substitution Reactions (SES_E): The halogen atom is deactivating but ortho/para directing due to the +R+R effect (resonance) and I-I effect (induction).

Major Electrophilic reactions include Halogenation, Nitration (conc.HNO3+H2SO4conc. HNO_3 + H_2SO_4), Sulphonation (conc.H2SO4conc. H_2SO_4), and Friedel-Crafts Alkylation/Acylation.

Wurtz-Fittig Reaction: A mixture of an alkyl halide and aryl halide treated with sodium in dry ether gives an alkylarene.

Fittig Reaction: Aryl halides when treated with sodium in dry ether give diphenyl (biphenyl).

📐Formulae

C6H5Cl+2NaOH623K,300atm(i)NaOH,(ii)H+C6H5OH+NaClC_6H_5Cl + 2NaOH \xrightarrow[623K, 300 atm]{(i) NaOH, (ii) H^+} C_6H_5OH + NaCl

C6H5Cl+Cl2Anhyd.FeCl31,4Dichlorobenzene(Major)+1,2Dichlorobenzene(Minor)C_6H_5Cl + Cl_2 \xrightarrow{Anhyd. FeCl_3} 1,4-Dichlorobenzene (Major) + 1,2-Dichlorobenzene (Minor)

C6H5Cl+CH3ClAnhyd.AlCl31Chloro4methylbenzene+1Chloro2methylbenzeneC_6H_5Cl + CH_3Cl \xrightarrow{Anhyd. AlCl_3} 1-Chloro-4-methylbenzene + 1-Chloro-2-methylbenzene

C6H5X+2Na+RXDry EtherC6H5R+2NaXC_6H_5X + 2Na + RX \xrightarrow{Dry\ Ether} C_6H_5-R + 2NaX

2C6H5X+2NaDry EtherC6H5C6H5+2NaX2C_6H_5X + 2Na \xrightarrow{Dry\ Ether} C_6H_5-C_6H_5 + 2NaX

💡Examples

Problem 1:

Explain why pp-nitrochlorobenzene is more reactive than chlorobenzene towards nucleophilic substitution with NaOHNaOH.

Solution:

The presence of the NO2-NO_2 group at the para position withdraws electrons from the benzene ring via the R-R effect. This decreases the electron density at the CClC-Cl bond and stabilizes the intermediate carbanion (Meisenheimer complex) formed during the reaction, making the nucleophilic attack by OHOH^- easier.

Explanation:

Electron-withdrawing groups at oo- and pp- positions facilitate SNS_N reactions in haloarenes by dispersing the negative charge of the sigma-complex.

Problem 2:

Predict the products of the reaction: Chlorobenzene+CH3COClAnhyd.AlCl3?Chlorobenzene + CH_3COCl \xrightarrow{Anhyd. AlCl_3} ?

Solution:

pp-Chloroacetophenone (Major) and oo-Chloroacetophenone (Minor).

Explanation:

This is a Friedel-Crafts Acylation reaction. The ClCl atom on the ring directs the incoming acyl group (CH3CO+CH_3CO^+) to the ortho and para positions. The para product is major due to less steric hindrance.

Reactions of haloarenes - Revision Notes & Key Formulas | ICSE Class 12 Chemistry