Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Physical Properties: Boiling points of alkyl halides follow the order due to the increase in forces with molecular mass. Among isomers, branching decreases the surface area, thus decreasing the boiling point.
Solubility: Haloalkanes are polar but are only sparingly soluble in water because they cannot form hydrogen bonds with water molecules. They are soluble in organic solvents.
Mechanism: A two-step nucleophilic substitution where the rate-determining step is the formation of a carbocation intermediate (). Reactivity order: . It is favored by polar protic solvents.
Mechanism: A single-step process involving the simultaneous attack of the nucleophile and departure of the leaving group through a transition state (). Reactivity order: due to steric hindrance.
Saytzeff's Rule: In dehydrohalogenation reactions, the major product is the alkene which has a greater number of alkyl groups attached to the doubly bonded carbon atoms (more substituted alkene).
Chemical Properties of Haloarenes: Haloarenes are less reactive towards nucleophilic substitution compared to haloalkanes due to resonance (partial double bond character of bond), hybridization of carbon, and instability of phenyl cation.
Electrophilic Substitution in Haloarenes: Halogens are deactivating but ortho- and para-directing due to effect (resonance) despite their effect.
Wurtz-Fittig and Fittig Reactions: Reaction of aryl halides with alkyl halides and sodium gives alkyl-substituted arenes (Wurtz-Fittig), while aryl halides reacting together give diphenyl (Fittig).
📐Formulae
💡Examples
Problem 1:
Predict the major product when -Bromopentane reacts with alcoholic .
Solution:
()
Explanation:
This is a -elimination reaction (dehydrohalogenation). According to Saytzeff's rule, the more substituted alkene is the major product. (disubstituted) is more stable and preferred over (monosubstituted).
Problem 2:
Which will undergo reaction faster: or ?
Solution:
(Ethyl chloride)
Explanation:
reactions proceed via a transition state and are highly sensitive to steric hindrance. is a primary halide with less steric crowding around the -carbon compared to the tertiary halide , allowing the nucleophile to attack more easily.
Problem 3:
Why is Chlorobenzene less reactive than Methyl chloride towards aqueous ?
Solution:
Due to resonance and hybridization.
Explanation:
In Chlorobenzene, the lone pair of enters into resonance with the benzene ring, giving the bond partial double bond character. Also, the atom in is hybridized (more electronegative), making the bond shorter and stronger than the bond in .