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Haloalkanes and Haloarenes - Optical rotation

Grade 12ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Optical Activity: The property of certain organic substances to rotate the plane of polarized light. Substances that rotate light to the right (clockwise) are called dextrorotatory (++ or dd), and those rotating it to the left (counter-clockwise) are laevorotatory (- or ll).

Chirality: A molecule is said to be chiral if it is non-superimposable on its mirror image. This usually occurs when a carbon atom is bonded to four different atoms or groups, known as an asymmetric carbon or chiral center (CC^*).

Enantiomers: Stereoisomers that are non-superimposable mirror images of each other. They have identical physical properties (like boiling point and solubility) but rotate plane-polarized light in opposite directions by equal magnitudes.

Racemic Mixture: An equimolar mixture of a pair of enantiomers. It is optically inactive because the rotation caused by one isomer is exactly cancelled by the rotation caused by the other. This is known as external compensation and is denoted by the prefix (±)(\pm) or dldl.

Racemization: The process of conversion of an enantiomer into a racemic mixture. This frequently occurs during SN1S_N1 reactions due to the formation of a planar carbocation intermediate.

Inversion of Configuration: In SN2S_N2 reactions, the nucleophile attacks from the side opposite to the leaving group, resulting in a product with a spatial arrangement opposite to the reactant, known as Walden Inversion.

📐Formulae

[α]λT=αl×c[\alpha]_{\lambda}^{T} = \frac{\alpha}{l \times c}

where [α]=Specific Rotation\text{where } [\alpha] = \text{Specific Rotation}

α=Observed angle of rotation (in degrees)\alpha = \text{Observed angle of rotation (in degrees)}

l=Path length of the sample tube in decimeters (dm)l = \text{Path length of the sample tube in decimeters } (dm)

c=Concentration of the solution in g/mLc = \text{Concentration of the solution in } g/mL

💡Examples

Problem 1:

Identify the chiral center in CH3CH(OH)COOHCH_3CH(OH)COOH (Lactic acid) and draw its enantiomers.

Solution:

The central carbon (carbon-2) is the chiral center as it is bonded to four different groups: H-H, OH-OH, CH3-CH_3, and COOH-COOH. The enantiomers are:

  1. dd-Lactic acid
  2. ll-Lactic acid

Explanation:

Because the molecule lacks a plane of symmetry and has a CC^* atom, it exists as two non-superimposable mirror images.

Problem 2:

Why is a racemic mixture of (±)(\pm)-2-chlorobutane optically inactive?

Solution:

A racemic mixture contains 50%50\% of the (+)(+) enantiomer and 50%50\% of the ()(-) enantiomer.

Explanation:

The optical rotation of +13.5+13.5^\circ (for example) by the dextro form is cancelled by the 13.5-13.5^\circ rotation of the laevo form. This net zero rotation is due to external compensation.

Problem 3:

A solution of an organic compound with concentration 0.5 g/mL0.5 \text{ g/mL} in a 2 dm2 \text{ dm} tube rotates plane polarized light by +10+10^\circ. Calculate the specific rotation.

Solution:

[α]=+102×0.5=+10[\alpha] = \frac{+10}{2 \times 0.5} = +10^\circ

Explanation:

Using the formula [α]=αl×c[\alpha] = \frac{\alpha}{l \times c}, we substitute the given values to find the standardized optical activity of the substance.

Optical rotation - Revision Notes & Key Formulas | ICSE Class 12 Chemistry