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Haloalkanes and Haloarenes - Nomenclature and nature of C-X bond

Grade 12ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Haloalkanes are compounds where one or more hydrogen atoms in an aliphatic hydrocarbon are replaced by halogen atoms (X=F,Cl,Br,IX = F, Cl, Br, I). Their general formula is R−XR-X.

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Haloarenes are compounds where one or more hydrogen atoms in an aromatic hydrocarbon are replaced by halogen atoms. The halogen is directly attached to an sp2sp^2 hybridized carbon of the benzene ring.

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Classification: Haloalkanes are classified as primary (1∘1^\circ), secondary (2∘2^\circ), or tertiary (3∘3^\circ) depending on the nature of the carbon atom to which the halogen is attached.

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IUPAC Nomenclature: Halogens are treated as substituent groups prefixed as fluoro-, chloro-, bromo-, or iodo-. The parent chain is the longest carbon chain containing the halogen, and numbering starts from the end nearest to the substituent.

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Nature of C-X bond: The carbon-halogen bond is polar due to the higher electronegativity of halogens compared to carbon, resulting in a partial positive charge on carbon (Cδ+C^{\delta+}) and a partial negative charge on the halogen (Xδ−X^{\delta-}).

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Bond Length Trend: Atomic size of halogens increases from FF to II, thus the C−XC-X bond length increases in the order: C−F<C−Cl<C−Br<C−IC-F < C-Cl < C-Br < C-I.

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Bond Enthalpy Trend: As bond length increases, bond strength decreases. Therefore, bond enthalpy decreases in the order: C−F>C−Cl>C−Br>C−IC-F > C-Cl > C-Br > C-I.

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Dipole Moment: Although FF is more electronegative than ClCl, the dipole moment of CH3ClCH_3Cl (1.860 D1.860\,D) is slightly higher than CH3FCH_3F (1.847 D1.847\,D) because of the significantly longer C−ClC-Cl bond length.

📐Formulae

CnH2n+1X (General formula for Monohaloalkanes)C_n H_{2n+1} X \text{ (General formula for Monohaloalkanes)}

μ=q×d (Dipole Moment)\mu = q \times d \text{ (Dipole Moment)}

Electronegativity: F>Cl>Br>I\text{Electronegativity: } F > Cl > Br > I

Bond Enthalpy: C−F>C−Cl>C−Br>C−I\text{Bond Enthalpy: } C-F > C-Cl > C-Br > C-I

💡Examples

Problem 1:

Write the IUPAC name of the following compound: CH3−CH(Cl)−CH(Br)−CH3CH_3-CH(Cl)-CH(Br)-CH_3.

Solution:

2-bromo-3-chlorobutane

Explanation:

The longest carbon chain has 4 carbons (butane). Numbering from either side gives substituents at positions 2 and 3. According to alphabetical order, 'bromo' comes before 'chloro', so the carbon attached to BrBr gets the lower number (2).

Problem 2:

Compare the C−XC-X bond length in CH3−ClCH_3-Cl and C6H5−ClC_6H_5-Cl (Chlorobenzene).

Solution:

C−ClC-Cl bond in C6H5−ClC_6H_5-Cl is shorter than in CH3−ClCH_3-Cl.

Explanation:

In chlorobenzene, the C−ClC-Cl bond has a partial double bond character due to resonance. Additionally, the carbon in haloarenes is sp2sp^2 hybridized (more ss-character, more electronegative), whereas in haloalkanes it is sp3sp^3 hybridized.

Problem 3:

Give the IUPAC name for (CH3)3CCH2Br(CH_3)_3CCH_2Br.

Solution:

1-bromo-2,2-dimethylpropane

Explanation:

The longest chain containing the halogen has 3 carbons (propane). There are two methyl groups at position 2 and a bromine at position 1. Alphabetically, bromo comes before methyl.