Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Phenol () is more acidic than alcohols but less acidic than carboxylic acids. Its acidic nature is demonstrated by its reaction with active metals (like ) and aqueous to form phenoxide salts.
The acidity of phenol is due to the formation of a stable phenoxide ion () after losing a proton. The negative charge on the oxygen atom is delocalized over the benzene ring through resonance, which stabilizes the ion.
In contrast, alcohols () form alkoxide ions () upon losing a proton. Alkoxide ions are not resonance-stabilized, and the effect of the alkyl group increases electron density on the oxygen, making the ion less stable.
The presence of Electron Withdrawing Groups (EWG) like , , or at ortho and para positions increases the acidity of phenol by stabilizing the phenoxide ion through and effects.
The presence of Electron Donating Groups (EDG) like or decreases the acidity of phenol because they increase the electron density on the oxygen atom, destabilizing the phenoxide ion through and effects.
Phenols do not react with sodium bicarbonate (), unlike carboxylic acids, because they are weaker acids than carbonic acid ().
📐Formulae
💡Examples
Problem 1:
Arrange the following compounds in increasing order of their acidic strength: Phenol, -Nitrophenol, -Cresol, and Ethanol.
Solution:
Ethanol < -Cresol < Phenol < -Nitrophenol
Explanation:
Ethanol is the least acidic because it is an alcohol. -Cresol contains a methyl group () which is an EDG, decreasing acidity compared to phenol. -Nitrophenol contains a nitro group (), which is a strong EWG that stabilizes the phenoxide ion, making it the most acidic.
Problem 2:
Why is -nitrophenol less acidic than -nitrophenol despite both having a nitro group?
Solution:
-Nitrophenol is slightly more acidic than -nitrophenol.
Explanation:
In -nitrophenol, intramolecular hydrogen bonding occurs between the and groups. This makes it more difficult for the proton () to be released compared to -nitrophenol, where no such intramolecular bonding exists.