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Chemical Bonding and Structure - Metallic bonding

Grade 12IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Metallic bonding is the strong electrostatic attraction between a regular lattice of positive metal ions (cations) and a 'sea' of delocalized valence electrons.

The strength of the metallic bond depends on the charge of the metal ion (Mn+M^{n+}) and the ionic radius (rr). Strength increases with higher charge and smaller radius (higher charge density).

Metals are excellent conductors of electricity and heat because the delocalized electrons are mobile and can carry charge or thermal energy throughout the structure.

Malleability and ductility occur because the non-directional nature of the metallic bond allows layers of cations to slide over each other without breaking the bond, as the 'sea' of electrons adjusts to the new positions.

Alloys are mixtures of metals with other elements (metal or non-metal). The presence of atoms of different sizes disrupts the regular lattice structure, making it more difficult for layers to slide, thus increasing hardness and strength compared to pure metals.

Trends in melting points: Melting points generally increase across a period (e.g., Na<Mg<AlNa < Mg < Al) as the number of delocalized electrons increases and ionic radius decreases, strengthening the metallic bond.

📐Formulae

Bond StrengthCharge of ionIonic radius\text{Bond Strength} \propto \frac{\text{Charge of ion}}{\text{Ionic radius}}

Current (I)=nqvdA\text{Current (I)} = nqv_d A

Density (ρ)=mV\text{Density (}\rho\text{)} = \frac{m}{V}

💡Examples

Problem 1:

Compare the melting points of Sodium (NaNa) and Magnesium (MgMg) based on their metallic bonding structure.

Solution:

MgMg has a higher melting point (650C650^\circ C) than NaNa (98C98^\circ C).

Explanation:

Magnesium atoms lose two valence electrons to form Mg2+Mg^{2+} ions, whereas sodium atoms lose only one to form Na+Na^+ ions. Mg2+Mg^{2+} has a higher nuclear charge and a smaller ionic radius than Na+Na^+. This results in a higher charge density in MgMg, leading to a stronger electrostatic attraction between the Mg2+Mg^{2+} cations and the larger 'sea' of delocalized electrons (2 electrons per atom vs 1 per atom in NaNa).

Problem 2:

Explain why Brass, an alloy of Copper (CuCu) and Zinc (ZnZn), is harder than pure Copper.

Solution:

The addition of ZnZn atoms to the CuCu lattice creates a 'pinning' effect.

Explanation:

Pure CuCu consists of identical atoms in a regular lattice that can easily slide over each other under stress. ZnZn atoms have a different atomic radius than CuCu atoms. When ZnZn is added to form an alloy, the regular arrangement of the CuCu lattice is distorted. This disruption prevents the layers of atoms from sliding over each other easily, making the material harder and less malleable.

Metallic bonding - Revision Notes & Key Formulas | IB Grade 12 Chemistry