Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
The bond is polar due to the electronegativity difference between Carbon and Halogen (). The dipole moment follows the order: .
Boiling Points: For the same alkyl group, the boiling point increases with the atomic mass of the halogen: . For isomeric haloalkanes, boiling point decreases with branching because the surface area decreases, weakening Van der Waals forces.
Solubility: Although polar, haloalkanes are only slightly soluble in because they cannot form hydrogen bonds with water molecules nor break the existing -bonds between water molecules.
Mechanism (Bimolecular Nucleophilic Substitution): Occurs in a single step via a pentacoordinate transition state. It involves the inversion of configuration (Walden Inversion). Reactivity order: .
Mechanism (Unimolecular Nucleophilic Substitution): Occurs in two steps involving a carbocation intermediate. It usually results in racemization. Reactivity order (based on carbocation stability): .
eta-Elimination (Dehydrohalogenation): When heated with alcoholic , haloalkanes form alkenes. According to Saytzeff's Rule, the highly substituted alkene (more alkyl groups attached to the double-bonded carbons) is the major product.
Reactivity of Haloarenes: They are extremely less reactive towards nucleophilic substitution due to resonance (partial double bond character of ), hybridization of carbon, and instability of the phenyl cation.
Electrophilic Substitution: In haloarenes, halogens are deactivating but - and -directing due to the effect (resonance) which increases electron density at and positions.
📐Formulae
💡Examples
Problem 1:
Arrange the following in increasing order of boiling point: -Chloropropane, Isopropyl chloride, -Chlorobutane.
Solution:
Isopropyl chloride < -Chloropropane < -Chlorobutane
Explanation:
-Chlorobutane has the highest molecular mass and surface area. Between -chloropropane and Isopropyl chloride (isomers), the branched Isopropyl chloride has a smaller surface area and thus lower Van der Waals forces.
Problem 2:
Which compound in the following pair will react faster in reaction with : or ?
Solution:
Explanation:
In reactions, the leaving group ability is crucial. Since the bond is weaker than the bond due to the larger size of the Iodine atom, is a better leaving group than .
Problem 3:
Predict the major product formed when -Bromopentane reacts with alcoholic .
Solution:
Explanation:
According to Saytzeff's Rule, the elimination of occurs to prefer the more substituted alkene. (with two alkyl groups on the double bond) is more stable and thus the major product compared to .