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Coordination Compounds - Isomerism in Coordination Compounds

Grade 12CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Isomerism in coordination compounds describes molecules with the same chemical formula but different structural arrangements or spatial orientations. It is broadly classified into Structural Isomerism and Stereoisomerism.

Structural Isomerism includes: 1. Linkage Isomerism (arises with ambidentate ligands like NO2NO_2^- or SCNSCN^-); 2. Ionization Isomerism (interchange of ions between the coordination sphere and the ionization sphere); 3. Coordination Isomerism (interchange of ligands between cationic and anionic entities); 4. Solvate Isomerism (differing number of H2OH_2O molecules inside the coordination sphere).

Stereoisomerism includes: 1. Geometrical Isomerism (cis/transcis/trans and fac/merfac/mer); 2. Optical Isomerism (chiral molecules that are non-superimposable mirror images).

Geometrical Isomerism: In square planar complexes of type [MA2B2][MA_2B_2], ciscis (adjacent) and transtrans (opposite) forms exist. In octahedral complexes of type [MA3B3][MA_3B_3], isomers are designated as facfac (facial) and mermer (meridional).

Optical Isomerism: Common in octahedral complexes containing chelating didentate ligands such as ethylenediamine (enen). Enantiomers are labeled as dd (dextro) and ll (laevo) based on their rotation of plane-polarized light.

📐Formulae

Square Planar: [MA2B2]cis,trans\text{Square Planar: } [MA_2B_2] \rightarrow cis, trans

Octahedral: [MA4B2]cis,trans\text{Octahedral: } [MA_4B_2] \rightarrow cis, trans

Octahedral: [MA3B3]fac,mer\text{Octahedral: } [MA_3B_3] \rightarrow fac, mer

Optical Activity: [M(en)3]n+d and l forms\text{Optical Activity: } [M(en)_3]^{n+} \rightarrow d \text{ and } l \text{ forms}

💡Examples

Problem 1:

Identify the type of isomerism exhibited by the pair [Co(NH3)5(SO4)]Br[Co(NH_3)_5(SO_4)]Br and [Co(NH3)5Br]SO4[Co(NH_3)_5Br]SO_4.

Solution:

Ionization Isomerism.

Explanation:

These isomers yield different ions in solution. [Co(NH3)5(SO4)]Br[Co(NH_3)_5(SO_4)]Br gives BrBr^- ions, whereas [Co(NH3)5Br]SO4[Co(NH_3)_5Br]SO_4 gives SO42SO_4^{2-} ions.

Problem 2:

How many geometrical isomers are possible for the square planar complex [Pt(NH3)(NH2OH)(Py)(Cl)]+[Pt(NH_3)(NH_2OH)(Py)(Cl)]^+?

Solution:

33 geometrical isomers.

Explanation:

For a square planar complex of type [MABCD][MABCD], three isomers are possible by fixing one ligand and rotating the other three.

Problem 3:

Explain why [Co(en)3]3+[Co(en)_3]^{3+} shows optical isomerism while trans[Co(NH3)4Cl2]+trans-[Co(NH_3)_4Cl_2]^+ does not.

Solution:

[Co(en)3]3+[Co(en)_3]^{3+} is chiral, whereas trans[Co(NH3)4Cl2]+trans-[Co(NH_3)_4Cl_2]^+ has a plane of symmetry.

Explanation:

Optical isomerism requires the absence of a plane of symmetry. In [Co(en)3]3+[Co(en)_3]^{3+}, the didentate ligands create a helical, non-superimposable structure. The transtrans-isomer of [Co(NH3)4Cl2]+[Co(NH_3)_4Cl_2]^+ is achiral due to its symmetrical arrangement.

Isomerism in Coordination Compounds Revision - Class 12 Chemistry CBSE