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Coordination Compounds - Bonding in Metal Carbonyls

Grade 12CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Metal carbonyls are coordination compounds formed between transition metals and Carbon Monoxide (COCO). They are mostly homoleptic complexes, such as [Ni(CO)4][Ni(CO)_4] and [Fe(CO)5][Fe(CO)_5].

The metal-carbon (MCM-C) bond in metal carbonyls possesses both ss and pp character (synergic bonding).

The σ\sigma-bond is formed by the donation of a lone pair of electrons on the carbonyl carbon into a vacant dd-orbital of the metal atom (MCM \leftarrow C).

The π\pi-bond is formed by the donation of a pair of electrons from a filled dd-orbital of the metal into the vacant anti-bonding π\pi^* orbital of the COCO ligand (MπCM \xrightarrow{\pi} C).

This MCM \to C back-donation is called back-bonding. It strengthens the MCM-C bond while simultaneously weakening the COC-O bond.

The 'Synergic Effect' refers to the mutual strengthening of the σ\sigma and π\pi bonds; σ\sigma-donation increases electron density on the metal, which enhances π\pi-back donation, and vice versa.

Structures: [Ni(CO)4][Ni(CO)_4] is tetrahedral, [Fe(CO)5][Fe(CO)_5] is trigonal bipyramidal, and [Cr(CO)6][Cr(CO)_6] is octahedral.

📐Formulae

Mσ bond:CO:M \xleftarrow{\sigma \text{ bond}} :C \equiv O:

Mπ back-bondπ orbital of COM \xrightarrow{\pi \text{ back-bond}} \pi^* \text{ orbital of } CO

Bond Order (C-O)1Extent of back-bonding\text{Bond Order (C-O)} \propto \frac{1}{\text{Extent of back-bonding}}

Metal Oxidation State    Back-bonding    C-O Bond Length\text{Metal Oxidation State} \downarrow \implies \text{Back-bonding} \uparrow \implies \text{C-O Bond Length} \uparrow

💡Examples

Problem 1:

Which of the following has the longest COC-O bond length: [Fe(CO)4]2[Fe(CO)_4]^{2-}, [Mn(CO)6]+[Mn(CO)_6]^+, or [Ni(CO)4][Ni(CO)_4]?

Solution:

[Fe(CO)4]2[Fe(CO)_4]^{2-} has the longest COC-O bond length.

Explanation:

In [Fe(CO)4]2[Fe(CO)_4]^{2-}, the metal has a high negative charge (2-2). This high electron density on the metal increases the extent of π\pi-back donation into the π\pi^* anti-bonding orbitals of COCO. More electron density in anti-bonding orbitals reduces the COC-O bond order and increases the COC-O bond length.

Problem 2:

Describe the hybridization and shape of [Ni(CO)4][Ni(CO)_4].

Solution:

sp3sp^3 hybridization and Tetrahedral shape.

Explanation:

In [Ni(CO)4][Ni(CO)_4], Nickel is in the 00 oxidation state ([Ar]3d84s2[Ar] 3d^8 4s^2). Carbon monoxide is a strong field ligand, causing the 4s4s electrons to pair into the 3d3d orbitals, resulting in a 3d103d^{10} configuration. The four COCO ligands then donate electron pairs into one 4s4s and three 4p4p orbitals, leading to sp3sp^3 hybridization.

Bonding in Metal Carbonyls - Revision Notes & Key Formulas | CBSE Class 12 Chemistry