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Amines - Importance of Diazonium Salts in Synthesis of Aromatic Compounds

Grade 12CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Diazonium salts have the general formula ArN2+Xβˆ’ArN_2^+X^-, where ArAr is an aryl group and Xβˆ’X^- is an ion such as Clβˆ’Cl^-, Brβˆ’Br^-, HSO4βˆ’HSO_4^-, or BF4βˆ’BF_4^-.

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Preparation (Diazotisation): Primary aromatic amines react with nitrous acid (produced in situ from NaNO2NaNO_2 and HClHCl) at 273βˆ’278K273-278 K to form diazonium salts. The temperature must be kept low to prevent decomposition.

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Physical Properties: Benzenediazonium chloride is a colorless crystalline solid, readily soluble in water, and stable in cold but reacts with water when warmed.

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Sandmeyer Reaction: Use of CuClCuCl, CuBrCuBr, or CuCNCuCN to replace the diazonium group with βˆ’Cl-Cl, βˆ’Br-Br, or βˆ’CN-CN respectively.

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Gattermann Reaction: A modification of the Sandmeyer reaction using copper powder in the presence of HClHCl or HBrHBr.

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Balz-Schiemann Reaction: Introduction of Fluorine onto the benzene ring by treating diazonium salt with fluoroboric acid (HBF4HBF_4) followed by heating.

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Replacement by Iodide: Unlike other halogens, iodine is introduced simply by shaking the diazonium salt with KIKI.

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Reduction to Arenes: Diazonium salts are reduced to benzene using mild reducing agents like phosphinic acid (H3PO2H_3PO_2) or ethanol (CH3CH2OHCH_3CH_2OH).

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Azo Coupling: Diazonium salts react with electron-rich aromatic compounds like phenols and amines to form brightly colored azo compounds (Arβˆ’N=Nβˆ’Arβ€²Ar-N=N-Ar'), which are used as dyes.

πŸ“Formulae

C6H5NH2+NaNO2+2HClβ†’273βˆ’278KC6H5N2+Clβˆ’+NaCl+2H2OC_6H_5NH_2 + NaNO_2 + 2HCl \xrightarrow{273-278 K} C_6H_5N_2^+Cl^- + NaCl + 2H_2O

ArN2+Xβˆ’β†’CuCl/HClArCl+N2ArN_2^+X^- \xrightarrow{CuCl/HCl} ArCl + N_2

ArN2+Xβˆ’β†’CuCN/KCNArCN+N2ArN_2^+X^- \xrightarrow{CuCN/KCN} ArCN + N_2

ArN2+Clβˆ’+KIβ†’ArI+KCl+N2ArN_2^+Cl^- + KI \rightarrow ArI + KCl + N_2

ArN2+Clβˆ’+HBF4β†’ArN2+BF4βˆ’β†’Ξ”ArF+BF3+N2ArN_2^+Cl^- + HBF_4 \rightarrow ArN_2^+BF_4^- \xrightarrow{\Delta} ArF + BF_3 + N_2

ArN2+Clβˆ’+H2Oβ†’warmArOH+N2+HClArN_2^+Cl^- + H_2O \xrightarrow{warm} ArOH + N_2 + HCl

ArN2+Clβˆ’+H3PO2+H2Oβ†’ArH+N2+H3PO3+HClArN_2^+Cl^- + H_3PO_2 + H_2O \rightarrow ArH + N_2 + H_3PO_3 + HCl

πŸ’‘Examples

Problem 1:

How will you convert Aniline to Fluorobenzene?

Solution:

C6H5NH2β†’NaNO2+HCl,273KC6H5N2+Clβˆ’β†’HBF4C6H5N2+BF4βˆ’β†’Ξ”C6H5F+BF3+N2C_6H_5NH_2 \xrightarrow{NaNO_2 + HCl, 273K} C_6H_5N_2^+Cl^- \xrightarrow{HBF_4} C_6H_5N_2^+BF_4^- \xrightarrow{\Delta} C_6H_5F + BF_3 + N_2

Explanation:

This is the Balz-Schiemann reaction. Aniline is first diazotized to benzenediazonium chloride, which then reacts with fluoroboric acid to form a precipitate of benzenediazonium fluoroborate. Upon heating, it decomposes to give fluorobenzene.

Problem 2:

Write the reaction for the coupling of Benzenediazonium chloride with Phenol.

Solution:

C6H5N2+Clβˆ’+C6H5OHβ†’OHβˆ’,pH9βˆ’10pβˆ’HOC6H4βˆ’N=Nβˆ’C6H5+Clβˆ’+H2OC_6H_5N_2^+Cl^- + C_6H_5OH \xrightarrow{OH^-, pH 9-10} p-HOC_6H_4-N=N-C_6H_5 + Cl^- + H_2O

Explanation:

This is an electrophilic substitution reaction where the diazonium cation acts as an electrophile. The reaction with phenol occurs in a weakly alkaline medium to produce pp-hydroxyazobenzene, which is an orange-colored dye.

Importance of Diazonium Salts in Synthesis of Aromatic Compounds Revision - Class 12 Chemistry CBSE